Question

在我的代码的一部分中，我将十进制坐标转换为度/分/秒，我使用它：

double coord = 59.345235;
int sec = (int)Math.Round(coord * 3600);
int deg = sec / 3600;
sec = Math.Abs(sec % 3600);
int min = sec / 60;
sec %= 60;

我如何从度/分/秒转换回小数点坐标？

Answer 1

试试这个：

public double ConvertDegreeAngleToDouble( double degrees, double minutes, double seconds )
{
    //Decimal degrees = 
    //   whole number of degrees, 
    //   plus minutes divided by 60, 
    //   plus seconds divided by 3600

    return degrees + (minutes/60) + (seconds/3600);
}

Answer 2

为了节省他人的时间，我想补充一下拜伦的答案。如果您有字符串形式的点（例如＆＃34; 17.21.18S＆＃34;），您可以使用此方法：

public double ConvertDegreeAngleToDouble(string point)
{
    //Example: 17.21.18S

    var multiplier = (point.Contains("S") || point.Contains("W")) ? -1 : 1; //handle south and west

    point = Regex.Replace(point, "[^0-9.]", ""); //remove the characters

    var pointArray = point.Split('.'); //split the string.

    //Decimal degrees = 
    //   whole number of degrees, 
    //   plus minutes divided by 60, 
    //   plus seconds divided by 3600

    var degrees = Double.Parse(pointArray[0]);
    var minutes = Double.Parse(pointArray[1]) / 60;
    var seconds = Double.Parse(pointArray[2]) / 3600;

    return (degrees + minutes + seconds) * multiplier;
}

Answer 3

由于度数总共1个坐标总数，分钟值为坐标总数的1/60，秒数值为坐标总数的1/3600，因此您应该能够将它们重新组合在一起：

new_coord = deg + min/60 + sec/3600

请注意，由于浮点舍入，它与原始版本不完全相同。

Answer 4

西半球和南半球通常表示为负度，秒数包含精度的小数：-86：44：52.892记住经度是X坐标，纬度是Y坐标。这通常会混淆，因为人们经常将它们称为纬度/经度和X / Y.我修改了以下格式的代码。

private double ConvertDegreesToDecimal(string coordinate)
{
    double decimalCoordinate;
    string[] coordinateArray = coordinate.Split(':');
    if (3 == coordinateArray.Length)
    {
        double degrees = Double.Parse(coordinateArray[0]);
        double minutes = Double.Parse(coordinateArray[1]) / 60;
        double seconds = Double.Parse(coordinateArray[2]) / 3600;

        if (degrees > 0)
        {
            decimalCoordinate = (degrees + minutes + seconds);
        }
        else
        {
            decimalCoordinate = (degrees - minutes - seconds);
        }
    }
    return decimalCoordinate;
}

Answer 5

日期接受的答案不准确，并未考虑向正数添加负数时会发生什么。以下代码解决了问题并将正确转换。

    public double ConvertDegreeAngleToDouble(double degrees, double minutes, double seconds)
    {
        var multiplier = (degrees < 0 ? -1 : 1);
        var _deg = (double)Math.Abs(degrees);
        var result = _deg + (minutes / 60) + (seconds / 3600);
        return result * multiplier;
    }

Answer 6

CoordinateSharp可用作Nuget包，可以为您处理协调转换。它甚至可以进行UTM / MGRS转换，并提供相对于输入位置的太阳/月球时间。它真的很容易使用！

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坐标属性也是iObservable。因此，如果您更改纬度分钟值，则其他所有内容都将更新。

Answer 7

对于那些喜欢正则表达式并处理DDMMSS.dddS等格式的人可以轻松更新此功能以处理其他格式。

C＃

Regex reg = new Regex(@"^((?<D>\d{1,2}(\.\d+)?)(?<W>[SN])|(?<D>\d{2})(?<M>\d{2}(\.\d+)?)(?<W>[SN])|(?<D>\d{2})(?<M>\d{2})(?<S>\d{2}(\.\d+)?)(?<W>[SN])|(?<D>\d{1,3}(\.\d+)?)(?<W>[WE])|(?<D>\d{3})(?<M>\d{2}(\.\d+)?)(?<W>[WE])|(?<D>\d{3})(?<M>\d{2})(?<S>\d{2}(\.\d+)?)(?<W>[WE]))$");

private double DMS2Decimal(string dms)
            {
                double result = double.NaN;            

                var match = reg.Match(dms);

                if (match.Success)
                {
                    var degrees = double.Parse("0" + match.Groups["D"]);
                    var minutes = double.Parse("0" + match.Groups["M"]);
                    var seconds = double.Parse("0" + match.Groups["S"]);
                    var direction = match.Groups["W"].ToString();
                    var dec = (Math.Abs(degrees) + minutes / 60d + seconds / 3600d) * (direction == "S" || direction == "W" ? -1 : 1);
                    var absDec = Math.Abs(dec);

                    if ((((direction == "W" || direction == "E") && degrees <= 180 & absDec <= 180) || (degrees <= 90 && absDec <= 90)) && minutes < 60 && seconds < 60)
                    {
                        result = dec;
                    }

                }

                return result;

            }

将度/分/秒转换为十进制坐标

7 个答案: