Question

我正在尝试使用Spring Security 3.1对Active Directory进行身份验证。我得到了认证，一切都很好。

<sec:ldap-server id="ldapServer" url="ldap://ldap/dc=sub,dc=domain,dc=com" port="389" />

<sec:authentication-manager erase-credentials="true"  >
    <sec:authentication-provider ref="ldapActiveDirectoryAuthProvider" />
</sec:authentication-manager>

<bean id="ldapActiveDirectoryAuthProvider" 
        class="org.springframework.security.ldap.authentication.ad.ActiveDirectoryLdapAuthenticationProvider">
    <constructor-arg value="domain" />
    <constructor-arg value="ldap://server:389/"/> 
</bean>

现在回答这个问题。如何处理用户角色以便我可以设置过滤器？

例如

<sec:intercept-url pattern="/**" access="ROLE_USER"/>

解决方案

我通过使用UserDetailContextMapper并将我的AD组映射到ROLE_USER，ROLE_ADMIN等，找到了如何执行此操作。

    <bean id="ldapActiveDirectoryAuthProvider" 
        class="org.springframework.security.ldap.authentication.ad.ActiveDirectoryLdapAuthenticationProvider">
    <constructor-arg value="domain" />
    <constructor-arg value="ldap://host:389/"/> 
    <property name="userDetailsContextMapper" ref="tdrUserDetailsContextMapper"/>
    <property name="useAuthenticationRequestCredentials" value="true"/>
</bean>

<bean id="tdrUserDetailsContextMapper" class="com.bla.bla.UserDetailsContextMapperImpl"/>

Mapper类：

public class UserDetailsContextMapperImpl implements UserDetailsContextMapper, Serializable{
    private static final long serialVersionUID = 3962976258168853954L;

    @Override
    public UserDetails mapUserFromContext(DirContextOperations ctx, String username, Collection<? extends GrantedAuthority> authority) {

        List<GrantedAuthority> mappedAuthorities = new ArrayList<GrantedAuthority>();


        for (GrantedAuthority granted : authority) {

            if (granted.getAuthority().equalsIgnoreCase("MY USER GROUP")) {
                mappedAuthorities.add(new GrantedAuthority(){
                    private static final long serialVersionUID = 4356967414267942910L;

                    @Override
                    public String getAuthority() {
                        return "ROLE_USER";
                    } 

                });
            } else if(granted.getAuthority().equalsIgnoreCase("MY ADMIN GROUP")) {
                mappedAuthorities.add(new GrantedAuthority() {
                    private static final long serialVersionUID = -5167156646226168080L;

                    @Override
                    public String getAuthority() {
                        return "ROLE_ADMIN";
                    }
                });
            }
        }
        return new User(username, "", true, true, true, true, mappedAuthorities);
    }

    @Override
    public void mapUserToContext(UserDetails arg0, DirContextAdapter arg1) {
    }
}

Answer 1

您还可以注入3.1中引入的GrantedAuthoritiesMapper作为修改作者的一般策略。另外，您可能希望SimpleGrantedAuthority用于GrantedAuthority实施。或者，您可以使用枚举，因为您有一组固定的值：

enum MyAuthority implements GrantedAuthority {
    ROLE_ADMIN,
    ROLE_USER;

    public String getAuthority() {
        return name();
    }
}


class MyAuthoritiesMapper implements GrantedAuthoritiesMapper {

    public Collection<? extends GrantedAuthority> mapAuthorities(Collection<? extends GrantedAuthority> authorities) {
        Set<MyAuthority> roles = EnumSet.noneOf(MyAuthority.class);

        for (GrantedAuthority a: authorities) {
            if ("MY ADMIN GROUP".equals(a.getAuthority())) {
                roles.add(MyAuthority.ROLE_ADMIN);
            } else if ("MY USER GROUP".equals(a.getAuthority())) {
                roles.add(MyAuthority.ROLE_USER);
            }
        }

        return roles;
    }
}

Answer 2

beans.xml中的角色必须与memberOf value属性的CN（公用名）完全匹配。您应该阅读有关目录基础知识的教程。

说有这个用户： CN=Michael-O,OU=Users,OU=department,DC=sub,DC=company,DC=net 在他的上下文中存在此memberOf值CN=Group Name,OU=Permissions,OU=Groups,OU=department,DC=sub,DC=company,DC=net

Bean将找到此memberOf值并提取Group Name。你beans.xml必须具有这个值。

使用spring security 3.1对使用活动目录进行身份验证时处理角色

解决方案

2 个答案: