我正在尝试将Spring Security与Active Directory用户名和密码一起使用。另外,我有一个数据库Roles表,它与包含Active Directory用户名的User表有关系(User表与Active Directory无关,它完全独立我只是把用户名放在那个表中所以我可以与角色匹配)
我正在关注这个例子 http://krams915.blogspot.com/2012/01/spring-security-31-implement_1244.html
问题是我无法在CustomUserDetailsService类的loadUserByUsername方法中看到密码的使用位置。
public UserDetails loadUserByUsername(String username) throws UsernameNotFoundException {
try {
org.krams.domain.User domainUser = userRepository.findByUsername(username);
boolean enabled = true;
boolean accountNonExpired = true;
boolean credentialsNonExpired = true;
boolean accountNonLocked = true;
return new User(
domainUser.getUsername(),
domainUser.getPassword().toLowerCase(),
enabled,
accountNonExpired,
credentialsNonExpired,
accountNonLocked,
getAuthorities(domainUser.getRole().getRole()));
} catch (Exception e) {
throw new RuntimeException(e);
}
}
根据我的理解,此行会针对数据库userRepository.findByUsername(username);
但是如何在那里使用lpad验证呢?我可以使用像http://www.javaxt.com/Tutorials/Windows/How_to_Authenticate_Users_with_Active_Directory
这样的身份验证实现更新
我正在尝试使用CustomUserDetailsContextMapper
XML
<authentication-manager >
<authentication-provider ref="ldapActiveDirectoryAuthProvider" />
</authentication-manager>
<beans:bean id="ldapActiveDirectoryAuthProvider"
class="org.springframework.security.ldap.authentication.ad.ActiveDirectoryLdapAuthenticationProvider">
<beans:constructor-arg value="domain" />
<beans:constructor-arg value="ldap://NAME/"/>
<beans:property name="userDetailsContextMapper" ref="tdrUserDetailsContextMapper"/>
<beans:property name="useAuthenticationRequestCredentials" value="true"/>
</beans:bean>
<beans:bean id="tdrUserDetailsContextMapper" class="com.test8.security8.service.CustomUserDetailsContextMapper"/>
自定义类
public class CustomUserDetailsContextMapper implements UserDetailsContextMapper, Serializable{
private static final long serialVersionUID = 3962976258168853984L;
@Override
public UserDetails mapUserFromContext(DirContextOperations ctx, String username, Collection<? extends GrantedAuthority> authority) {
String role="admin";
System.out.println("TEST");
if(username.equals("usuario"))role="admin";
else role="user";
List authList = getAuthorities(role);
return new User(username, "", true, true, true, true, authList);
}
private List getAuthorities(String role) {
List authList = new ArrayList();
authList.add(new SimpleGrantedAuthority("ROLE_USER"));
//you can also add different roles here
//for example, the user is also an admin of the site, then you can add ROLE_ADMIN
//so that he can view pages that are ROLE_ADMIN specific
if (role != null && role.trim().length() > 0) {
if (role.equals("admin")) {
authList.add(new SimpleGrantedAuthority("ROLE_ADMIN"));
}
}
return authList;
}
@Override
public void mapUserToContext(UserDetails arg0, DirContextAdapter arg1) {
// TODO Auto-generated method stub
}
}
我想我差不多了,我没有收到错误,但它似乎无法映射任何用户,System.out.println("TEST")
;行永远不会执行。它可能是与URL /域相关的东西吗?我确定URL是正确的,因为如果我更改它,我会收到错误。
答案 0 :(得分:0)
我最终使用了M.Deinum建议的UserDetailsContextMapper。我还创建了风俗SpringSecurityLdapTemplate和ActiveDirectoryLdapAuthenticationProvider。
在我的自定义ActiveDirectoryLdapAuthenticationProvider中,我更改了以下方法:
private LdapContext bindAsUser(String username, String password) {
// TODO. add DNS lookup based on domain
final String bindUrl = url;
Hashtable<String,String> env = new Hashtable<String,String>();
env.put(Context.SECURITY_AUTHENTICATION, "simple");
String bindPrincipal = createBindPrincipal(username);
env.put(Context.SECURITY_PRINCIPAL, bindPrincipal);
env.put(Context.PROVIDER_URL, bindUrl);
env.put(Context.SECURITY_CREDENTIALS, password);
env.put(Context.INITIAL_CONTEXT_FACTORY, "com.sun.jndi.ldap.LdapCtxFactory");
env.put(Context.REFERRAL, "follow");
try {
return new InitialLdapContext(env, null);
} catch (NamingException e) {
if ((e instanceof AuthenticationException) || (e instanceof OperationNotSupportedException)) {
handleBindException(bindPrincipal, e);
throw badCredentials();
} else {
throw LdapUtils.convertLdapException(e);
}
}
}
这对我来说很重要: env.put(Context.REFERRAL,“follow”);
在SpringSecurityLdapTemplate自定义类
中public static DirContextOperations searchForSingleEntryInternal(DirContext ctx, SearchControls searchControls,
String base, String filter, Object[] params) throws NamingException {
final DistinguishedName ctxBaseDn = new DistinguishedName(ctx.getNameInNamespace());
final DistinguishedName searchBaseDn = new DistinguishedName(base);
final NamingEnumeration<SearchResult> resultsEnum = ctx.search(searchBaseDn, filter, params, buildControls(searchControls));
filter, searchControls);
if (logger.isDebugEnabled()) {
logger.debug("Searching for entry under DN '" + ctxBaseDn
+ "', base = '" + searchBaseDn + "', filter = '" + filter + "'");
}
Set<DirContextOperations> results = new HashSet<DirContextOperations>();
try {
while (resultsEnum.hasMore()) {
SearchResult searchResult = resultsEnum.next();
DirContextAdapter dca = new DirContextAdapter();
//dca=(DirContextAdapter) searchResult.getObject();
Assert.notNull(dca, "No object returned by search, DirContext is not correctly configured");
if (logger.isDebugEnabled()) {
logger.debug("Found DN: " + dca.getDn());
}
results.add(dca);
}
} catch (PartialResultException e) {
LdapUtils.closeEnumeration(resultsEnum);
logger.info("Ignoring PartialResultException");
}
if (results.size() == 0) {
throw new IncorrectResultSizeDataAccessException(1, 0);
}
if (results.size() > 1) {
throw new IncorrectResultSizeDataAccessException(1, results.size());
}
return results.iterator().next();
}
这对我有用,但这是一个非常特殊的场景。感谢M. Deinum指出我正确的方向。