Question

祝贺所有人。我有一个SQL 2008 express数据库，让name为tbl_Merchant，类似如下：

Merchant | Sales | Month
Comp.1      100     1
Comp.2      230     1
Comp.3      120     1
Comp.1      200     2
Comp.2      130     2
Comp.3      240     2
Comp.1      250     3
  .          .      .
  .          .      .
  .          .      .

我需要在12个月内找到每月销售额排名前10位的商家。

如果仅仅一个月就很容易。

SELECT TOP 10 
       Merchant, 
       Sales, 
       Month
FROM   tbl_Merchant
WHERE  Month = 1
ORDER BY Sales DESC

但如果我想在12个月内找到它们，我就会陷入困境。我需要展示120个商家，这是每个月的前十大销售商。目前我的解决方案是将第1个月到第12个月的12个表合并在一起，但我不认为这是一个好方法。

任何人都可以给我任何建议吗？

非常感谢。

Answer 1

适用于Sql Server 2005 +

整体尝试：

SELECT TOP 10 
       Merchant, 
       SUM(Sales) Sales
FROM   tbl_Merchant
WHERE  Month BETWEEN 1 and 12
GROUP BY Merchant
ORDER BY 2 DESC

或

如果您每月需要详细信息，前10名每月

;WITH MonthsCTE(m) as
(
    SELECT 1 m
    UNION ALL 
    SELECT m+1
    FROM MonthsCTE
    WHERE m < 12
)
SELECT m [Month], t.*
FROM MonthsCTE
CROSS APPLY 
(
    SELECT TOP 10
       Merchant, 
       SUM(Sales) Sales
    FROM   tbl_Merchant
    WHERE  Month = MonthsCTE.m
    GROUP BY Merchant
    ORDER BY 2 DESC
) t

Answer 2

尝试：

select * from
(SELECT Merchant, 
        Sales, 
        Month,
        row_number () over (partition by Month order by Sales desc) rn
 FROM   tbl_Merchant
 WHERE  Month between 1 and 12) v
where rn <= 10
order by Month, Sales desc

（应该在SQLServer中工作;不确定Sybase。）

Answer 3

select Top 10 
         SaleID, 
         sum(Salelines) As LINESUM
Into #TOP10sales
from salestable
group by SaleID
order by sum(Salelines) asc;

Then confirm the sales are top 10

select * 
from #TOP10sales;

Then.

Select field..
       field..
       field..
from #TOP10sales 
Inner Join salestable on #TOP10sales.ID = salestable.ID;

Answer 4

可以尝试以下方法：

SELECT top 10 Merchant,
isnull(SUM(CASE WHEN Month(ta.dt) = '01' THEN Sales END),0) AS "Jan Sales",
isnull(SUM(CASE WHEN Month(ta.dt) = '02' THEN Sales END),0) AS "Feb Sales",
isnull(SUM(CASE WHEN Month(ta.dt) = '03' THEN Sales END),0) AS "Mar Sales",
isnull(SUM(CASE WHEN Month(ta.dt) = '04' THEN Sales END),0) AS "Apr Sales",
isnull(SUM(CASE WHEN Month(ta.dt) = '05' THEN Sales END),0) AS "May Sales",
isnull(SUM(CASE WHEN Month(ta.dt) = '06' THEN Sales END),0) AS "Jun Sales",
isnull(SUM(CASE WHEN Month(ta.dt) = '07' THEN Sales END),0) AS "Jul Sales",
isnull(SUM(CASE WHEN Month(ta.dt) = '08' THEN Sales END),0) AS "Aug Sales",
isnull(SUM(CASE WHEN Month(ta.dt) = '09' THEN Sales END),0) AS "Sep Sales",
isnull(SUM(CASE WHEN Month(ta.dt) = '10' THEN Sales END),0) AS "Oct Sales",
isnull(SUM(CASE WHEN Month(ta.dt) = '11' THEN Sales END),0) AS "Nov Sales",
isnull(SUM(CASE WHEN Month(ta.dt) = '12' THEN Sales END),0) AS "Dec Sales"

FROM tbl_Merchant ORDER BY Sales DESC

每个月的十大销售额将按月显示为不同的列。

希望它有所帮助。

Answer 5

每月前10名的详细信息也可以使用此查询得出

选择商家，SUM（销售）Total_sales，月份为Monthofyear
来自tbl_Merchant
按月分组，商家，销售
按月销售，销售额说明

Answer 6

select top 10 Merchant, sum(Sales) from tbl_Merchant group by Merchant order by sum(Sales) desc

我更喜欢postgresql，但我认为它可以在没有（或很少）修改mssql的情况下工作

SQL每月十大销售额

6 个答案: