Question

我有一个格式的mysql表，我们称之为product_revenue Product_id，年，月，收入

我需要获得以下列：年，月，revenue_top_5_monthly

其中revenue_top_5_monthly是该月收入最高的产品的收入总和。前5个产品每个月都有所不同。

我可以通过一个月的子查询选择，按收入排序并使用限制5，然后总结值，我可以在一个月内执行此操作，但我不知道如何在每个月执行此操作单个查询

我拥有的是

select 'y' as year, 'x' as month, sum(revenue) as revenue_top_5 from
(select revenue from product_revenue
where month=x and year=y
order by revenue desc
limit 5) as top5

但我每个月都需要一次拍摄。

product_revenue表有16个月超过10米的行，因此最终查询速度具有很大的相关性。一个月它目前需要大约80-100秒，我必须在1小时30分钟的时间内运行大约30个这样的查询，每个查询整个16个月。

如建议的那样，我也试过了

select * from
(
select dd.year, dd.monthnumber,
u.product_id, sum(revenue) as revenue
from source
group by 1,2,3
)a
where 
(select count(*) from
                            (select dd.year, dd.monthnumber,
                            u.product_id, sum(revenue) as revenue
                            from source
                            group by 1,2,3)b
where b.year=a.year and b.monthnumber=a.monthnumber and b.revenue<=a.revenue
)<=5

但不返回任何行。各个子查询a和b将预期的行返回为named。

Answer 1

尝试此查询

select * from
(select 
@rn:=if(@prv=product_id, @rn+1, 1) as rId,
@prv:=product_id as product_id,
year, 
month,
revenue
from tbl
join
(select @prv:=0, @rn:=0)tmp
order by 
product_id, revenue desc) a
where rid<=5

的 SQL FIDDLE ：

| RID | PRODUCT_ID | YEAR | MONTH | REVENUE | --------------------------------------------- | 1 | 1 | 2013 | 1 | 100 | | 2 | 1 | 2013 | 1 | 90 | | 3 | 1 | 2013 | 1 | 70 | | 4 | 1 | 2013 | 1 | 60 | | 5 | 1 | 2013 | 1 | 50 | | 1 | 2 | 2013 | 1 | 5550 | | 2 | 2 | 2013 | 1 | 550 | | 3 | 2 | 2013 | 1 | 520 | | 4 | 2 | 2013 | 1 | 510 | | 5 | 2 | 2013 | 1 | 150 |

Answer 2

也许：

   SELECT t1.year,
          t1.month,
          (SELECT SUM(t2.revenue) 
           FROM product_revenue t2
           WHERE t2.month = t1.month
           AND t2.year = t1.year
           ORDER BY t2.revenue DESC LIMIT 5 ) AS revenue_top_5
   FROM product_revenue t1
   GROUP BY  t1.year, t1.month

Answer 3

试试这个和c。

select top 5 'y' as year,'x' as month,sum(total) as top_5 From
(select sum(revenue) as total from product_revenue
where month=x and year=y
order by revenue desc) as t

sql每月选择前5名

3 个答案:

的 SQL FIDDLE ：