Bass.dll只是Spectrum数据C#

时间:2012-01-04 09:17:58

标签: c# spectrum bass.dll

我正在尝试创建一个基于节拍和频谱检测的游戏。我目前坚持认为我的函数返回的不是我想要的,因为数组没有完全分配。填写的最后一个元素是错误的,我不知道为什么。

数组大小为20,此代码仅填充12或更少

  float[] rmsData;

    public void spektrsw(int barrcount, bool lefton, out float[] spectrumData)
    {
       spectrumData = new float[barrcount]; 
             //defining array in which will  be spectrum data
        if (isPlaying) //check if sound is playing
        {
            int lenght = (int)Bass.BASS_ChannelSeconds2Bytes(ActiveStreamHandle, 1.0); //gets and sets lenght
            int rmsDataArraySize = Math.Abs(lenght / 4); 
              //calculating FFT data or RMS array size 
            if (rmsData == null || rmsData.Length < rmsDataArraySize)
                 rmsData = new float[rmsDataArraySize]; 
                    //defining new array if old one has lenght smaler

            lenght = Bass.BASS_ChannelGetData(ActiveStreamHandle, rmsData, lenght); //geting lenght FFT data
            rmsDataArraySize = lenght / 4; //calculating FFT data or RMS array size 

            int times = (int)(rmsDataArraySize / (barrcount * 2)) + 1; 
   //calculating how many times loop will continue until the loop will go to next index

            int index = 0; 
   // creating index variable which will point to an element in array

            for (int counter = 0; counter < rmsDataArraySize; counter++)
            {

                if (counter % 2 == 0 || counter == 0) //For left channel
                {
                   if(lefton) //which channel am i analysing
                    spectrumData[index] = spectrumData[index] +  Math.Abs(rmsData[counter]);
                    //adding data to array
                }
                else
                {
                    if (!lefton) //which channel am i analysing
                        spectrumData[index] = spectrumData[index] + Math.Abs(rmsData[counter]);
                    //adding data to array
                }

                if (counter == times) //check to see if index needs to be increased
                {

                    spectrumData[index] = spectrumData[index] / times;
                    //this is for calculating avarege in one bar since
                    //I combined lots of data in one bar

                    spectrumData[index] = spectrumData[index] * 1000f;

                    index++;//increasing index
                    times = times + counter;

                }
            }                
        }          
    }

问题是:

  1. 我做对了吗?
  2. 为什么它不会返回所有值?
  3. 获取所需数据的最简单方法是什么?
  4. 坦克为你的答案准备好了。

    我很抱歉我的英语不好......

    [编辑]

    我发现if语句或我计算时间错误的方式: - (

    因此,如果您更好地了解如何从4000个元素的数组中获取数据到20个数组,如果您在此发布您的建议,我将很高兴。

0 个答案:

没有答案