Question

我是Android的初学者。在我的项目中，我从HTTP响应中获取了以下json。

[{"Date":"2012-1-4T00:00:00",
"keywords":null,
"NeededString":"this is the sample string I am needed for my project",
"others":"not needed"}]

我想从上面的json中获取“NeededString”。如何获得它？

Answer 1

这可能会对你有帮助。

<强> 爪哇：

JSONArray arr = new JSONArray(result);
JSONObject jObj = arr.getJSONObject(0);
String date = jObj.getString("NeededString");

<强> 科特林：

val jsonArray = JSONArray(result)
val jsonObject: JSONObject = jsonArray.getJSONObject(0)
val date= jsonObject.get("NeededString")

Answer 2

你只需要获取JSONArray并使用循环迭代数组内的JSONObject，但在你的情况下它只有一个JSONObject但你可能有更多。

JSONArray mArray;
        try {
            mArray = new JSONArray(responseString);
             for (int i = 0; i < mArray.length(); i++) {
                    JSONObject mJsonObject = mArray.getJSONObject(i);
                    Log.d("OutPut", mJsonObject.getString("NeededString"));
                }
        } catch (JSONException e) {
            e.printStackTrace();
        }

Answer 3

在项目中加入org.json.jsonobject。

然后你可以这样做：

JSONObject jresponse = new JSONObject(responseString);
responseString = jresponse.getString("NeededString");

假设responseString保留您收到的回复。

如果您需要知道如何将收到的响应转换为字符串，请按以下步骤操作：

ByteArrayOutputStream out = new ByteArrayOutputStream();
response.getEntity().writeTo(out);
out.close();
String responseString = out.toString();

Answer 4

您可以使用public static void main(String[] args) { Scanner Scan = new Scanner(System.in); int[] nums = new int[3]; System.out.print ("Enter a number: "); String num = Scan.nextLine(); num = num.trim(); for(int i = 0; i < num.length(); i++){ int digit = Integer.parseInt("" + num.charAt(i)); if(digit == 0){ nums[0]++; }else if(digit % 2 == 0){ nums[2]++; }else{ nums[1]++; } } System.out.print("The number: " + num + " has " + nums[0] + " zeros, " + nums[2] + " evens, " + "and " + nums[1] + " odds."); Scan.close(); }

getString

或String name = jsonObject.getString("name"); // it will throws exception if the key you specify doesn't exist

optString

Answer 5

如果您可以使用JSONObject库，则可以

    JSONArray ja = new JSONArray("[{\"Date\":\"2012-1-4T00:00:00\",\"keywords\":null,\"NeededString\":\"this is the sample string I am needed for my project\",\"others\":\"not needed\"}]");
    String result = ja.getJSONObject(0).getString("NeededString");

Answer 6

我认为这对你有帮助

                JSONArray jre = objJson.getJSONArray("Result");

                for (int j = 0; j < jre.length(); j++) {
                    JSONObject jobject = jre.getJSONObject(j);

                    String  date = jobject.getString("Date");
                    String  keywords=jobject.getString("keywords");
                    String  needed=jobject.getString("NeededString");

                }

Answer 7

这是我用过的解决方案适用于从字符串

获取JSON

protected String getJSONFromString(String stringJSONArray) throws JSONException {
        return new StringBuffer(
               new JSONArray(stringJSONArray).getJSONObject(0).getString("cartype"))
                   .append(" ")
                   .append(
               new JSONArray(employeeID).getJSONObject(0).getString("model"))
              .toString();
    }

Answer 8

这是从ResponseEntity获取元素的代码

try { final ResponseEntity responseEntity = restTemplate.exchange(API_URL, HttpMethod.POST, entity, String.class); log.info("responseEntity"+responseEntity); final JSONObject jsonObject ; if (responseEntity.getStatusCode() == HttpStatus.CREATED) { try { jsonObject = new JSONObject(responseEntity.getBody()); final String strName = jsonObject.getString("name"); log.info("name:"+strName); } catch (JSONException e) { throw new RuntimeException("JSONException occurred"); } } }catch (HttpStatusCodeException exception) { int statusCode = exception.getStatusCode().value(); log.info("statusCode:"+statusCode); }

Answer 9

请参阅以下答案，以上面的答案为灵感，但要更详细...

// Get The Json Response (With Try Catch)
try {

    String s = null;

    if (response.body() != null) {

        s = response.body().string();

        // Convert Response Into Json Object (With Try Catch)
        JSONObject json = null;

        try {
            json = new JSONObject(s);

            // Extract The User Id From Json Object (With Try Catch)
            String stringToExtract = null;

            try {
                stringToExtract = json.getString("NeededString");

            } catch (JSONException e) {
                e.printStackTrace();
            }

        } catch (JSONException e) {
            e.printStackTrace();
        }

    }

} catch (IOException e) {
    e.printStackTrace();
}

从Json Object Android获取字符串值

9 个答案: