在我的django应用程序中,即使我添加与管理应用程序中相同的数据,表单也永远不会返回true。我的model.py看起来像:
from django.db import models
from django.db.models import ImageField, signals
from django.dispatch import dispatcher
from django.forms import ModelForm
# Create your models here.
class Image(models.Model):
emailAddress = models.EmailField(max_length=75)
image = ImageField(upload_to='photos')
caption = models.CharField(max_length=100)
class UploadForm(ModelForm):
class Meta:
model = Image
我的views.py看起来像:
from django.http import HttpResponse, HttpResponseRedirect
from django.shortcuts import render_to_response
from competition.models import Image, UploadForm
# Create your views here.
def index(request):
images = Image.objects.all().order_by('emailAddress')
return render_to_response('images/index.html', {'images': images})
def uploadImage(request):
if request.method == 'POST': # If the form has been submitted...
form = UploadForm(request.POST) # A form bound to the POST data
if form.is_valid(): # All validation rules pass
emailAddress = form.cleaned_data['emailAddress']
image = form.cleaned_data['image']
caption = form.cleaned_data['caption']
i = Image(emailAddress=emailAddress, image = image, caption = caption)
i.save()
return HttpResponseRedirect('../image/')
else:
return render_to_response('images/upload.html', {'form': form})
else:
form = UploadForm() # An unbound form
return render_to_response('images/upload.html', {'form': form})
我的模板如下:
<html>
<body>
<form enctype="multipart/form-data" action="/image/uploadImage" method="post">{% csrf_token %}
{{ form.as_p }}
<input type="submit" value="Submit" />
</form>
</body>
</html>
如果我使用管理应用程序但需要通用表单,我可以正常工作,这不起作用,因为它一直要求电子邮件地址或图像(错误出现在图像字段上方)。那么为什么我的表格无效?
答案 0 :(得分:4)
您需要使用request.FILES以及request.POST实例化您的表单。
另外,您可以保存模型表单,而不是在视图中手动创建图像。
答案 1 :(得分:4)
您有一个必需的图片,但您没有将文件数据绑定到表单。
form = UploadForm(request.POST)
应该是
form = UploadForm(request.POST, request.FILES)
请参阅https://docs.djangoproject.com/en/1.3/ref/forms/api/#binding-uploaded-files
答案 2 :(得分:0)
FileField 和 ImageField 字段有两个地方需要注意:
enctype="multipart/form-data"
。<form enctype="multipart/form-data" method="post" action="/foo/">
request.FILES
作为表单构造函数。form = UploadFileForm(request.POST, request.FILES)
请参考:
https://docs.djangoproject.com/en/2.2/topics/http/file-uploads/ https://docs.djangoproject.com/en/2.2/ref/forms/api/#binding-uploaded-files