views.py

Question

我正在学习Django并且遇到一些形式问题。我尝试创建一个简单的表单，在其中键入名称并在另一页上显示。但是is_valid（）总是返回false。请帮我查一下我的错误

forms.py

from django import forms

class OrderForm(forms.Form):
    user=forms.CharField(max_length=100)

views.py

def order(request):
    return render(request, 'myapp/order.html', {})


def contact(request):
    username='not logged'

    if request.method == 'POST' :
        form=OrderForm(request.POST)

        if form.is_valid():
            username=form.cleaned_data['username']
        else:
            username='not worked'
    else:
        form=OrderForm()

    return render(request, 'myapp/contacts.html', {'username':username})

order.html

<form name = "form" action = "{% url 'contact' %}" method = "POST" >
    {% csrf_token %}
        <input type="text" name="username" placeholder="Name">
        <button type="submit">Login</button>
</form>

contacts.html

You are : <strong>{{ username }}</strong>

Answer 1

您的表单控件在HTML中的名称为username，而您的表单在Django中的名称为user。因此，表单字段中没有设置任何内容。

通常，您将表单放入上下文中，然后将其呈现为{{ form }}之类，或呈现每个字段，而不是构建自己的表单控件。文档显示了如何：https://docs.djangoproject.com/en/1.10/topics/forms/#working-with-form-templates

Answer 2

views.py

    from forms import OrderForm
    def order(request):
        form = OrderForm()
        return render(request, 'myapp/order.html', {"form" : form})

order.html

<form name = "form" action = "{% url 'contact' %}" method = "POST" >
    {% csrf_token %}
        {{form.as_p}}
        <button type="submit">Login</button>
</form>

在呈现模板时 {{form.as_p}} 看起来像

<p><label for="id_username">Username:</label>
    <input id="id_username" type="text" name="username" maxlength="100" required /></p>

Django，表单is_valid（）始终为false

2 个答案:

views.py

order.html