Question

如果我有以下内容：

{"hdrs": ["Make","Model","Year"],
 "data" : [ 
   {"Make":"Honda","Model":"Accord","Year":"2008"}
   {"Make":"Toyota","Model":"Corolla","Year":"2008"}
   {"Make":"Honda","Model":"Pilot","Year":"2008"}]
}

我有一个“hdrs”名称（即“Make”），如何引用data数组实例？似乎data["Make"][0]应该有效...但无法获得正确的参考

编辑

很抱歉有歧义..我可以遍历hdrs来获取每个hdr名称，但我需要使用hdrs的每个实例值来查找data中的所有数据元素（不确定是否有更好的解释）。我将在变量t中使用它，因为它是JSON（感谢重新标记）我希望能够引用这样的内容：t.data[hdrs[i]][j]

Answer 1

我不得不改变你的代码：

var x = {"hdrs": ["Make","Model","Year"],
         "data" : [ 
           {"Make":"Honda","Model":"Accord","Year":"2008"},
           {"Make":"Toyota","Model":"Corolla","Year":"2008"},
           {"Make":"Honda","Model":"Pilot","Year":"2008"}]
        };

        alert( x.data[0].Make );

编辑：回复您的编辑

var x = {"hdrs": ["Make","Model","Year"],
         "data" : [ 
           {"Make":"Honda","Model":"Accord","Year":"2008"},
           {"Make":"Toyota","Model":"Corolla","Year":"2008"},
           {"Make":"Honda","Model":"Pilot","Year":"2008"}]
        };
var Header = 0; // Make
for( var i = 0; i <= x.data.length - 1; i++ )
{
    alert( x.data[i][x.hdrs[Header]] );
}

Answer 2

那么，像这样？

var theMap = /* the stuff you posted */;
var someHdr = "Make";
var whichIndex = 0;
var correspondingData = theMap["data"][whichIndex][someHdr];

如果我理解正确的话，这应该有用......

Answer 3

var x = {"hdrs": ["Make","Model","Year"],
 "data" : [ 
   {"Make":"Honda","Model":"Accord","Year":"2008"}
   {"Make":"Toyota","Model":"Corolla","Year":"2008"}
   {"Make":"Honda","Model":"Pilot","Year":"2008"}]
};

x.data[0].Make == "Honda"
x['data'][0]['Make']  == "Honda"

你有向后的数组/哈希查找:)

Answer 4

首先，您忘记了数据数组项中的尾随逗号。

尝试以下方法：

var obj_hash = {
    "hdrs": ["Make","Model","Year"],
    "data" : [
        {"Make":"Honda","Model":"Accord","Year":"2008"},
        {"Make":"Toyota","Model":"Corolla","Year":"2008"},
        {"Make":"Honda","Model":"Pilot","Year":"2008"},
    ]
};

var ref_data = obj_hash.data;

alert(ref_data[0].Make);

@ Kent Fredric：请注意，最后一个逗号不是严格需要的，但允许您更轻松地移动线条（即，如果您在最后一行之后移动或添加它，它没有逗号，你必须特别记得添加一个逗号。我认为最好总是留下逗号。）

Answer 5

我不确定我理解你的问题，但是......

假设上面的JSON是var obj，你想要：

obj.data[0]["Make"] // == "Honda"

如果您只想引用第一个标题引用的字段，它将类似于：

obj.data[0][obj.hdrs[0]] // == "Honda"

Answer 6

也许尝试数据[0]。制作

Answer 7

关闭，你要用

var x = data[0].Make;
var z = data[0].Model;
var y = data[0].Year;

Answer 8

显示的代码在语法上不正确;它需要一些逗号。我得到了这个工作：

$foo = {"hdrs": ["Make","Model","Year"],
 "data" : [ 
   {"Make":"Honda","Model":"Accord","Year":"2008"},
   {"Make":"Toyota","Model":"Corolla","Year":"2008"},
   {"Make":"Honda","Model":"Pilot","Year":"2008"}]
};

然后我可以访问数据：

$foo["data"][0]["make"]

Answer 9

在答案的帮助下（以及在内部和外部循环正确之后）我得到了这个工作：

var t = eval( "(" + request + ")" ) ;
for (var i = 0; i < t.data.length; i++) {
 myTable +=    "<tr>";
 for (var j = 0; j < t.hdrs.length; j++) {
  myTable += "<td>" ;
   if (t.data[i][t.hdrs[j]] == "") {myTable += "&nbsp;" ; }
    else { myTable += t.data[i][t.hdrs[j]] ; }
  myTable += "</td>";
 }
 myTable +=    "</tr>";
}

Javascript数组引用

9 个答案: