目前我可以正确解析这样的JSON:
"assignments:[{"
+ "'id': '111',"
+ "'erporder_erpid' : '132',"
+ "'dtStart' : '10:00 12-12-12',"
+ "}]";
与GSON合作。但我不知道解析多个对象的适当方法,如:
"assignments:[{"
+ "'id': '111',"
+ "'erporder_erpid' : '132',"
+ "'dtStart' : '10:00 12-12-12',"
+ "},"
+ "{"
+ "'id': '111',"
+ "'erporder_erpid' : '132',"
+ "'dtStart' : '10:00 12-12-12',"
+ "}]"
我正确设置了Javabean。
答案 0 :(得分:3)
您可以使用以下方法:
JSONArray outerArr = new JSONArray("assignments");
for(int ictr=0;ictr<outerArr.length;ictr++)
{
JSONObject obj =outerArr.getJSONObject(ictr);
String id=obj.getString("id");
String erporder_erpid=obj.getString("erporder_erpid");
String dtStart=obj.getString("dtStart");
}
希望这对你有所帮助。
答案 1 :(得分:3)
{
"assignments:[{"
+ "'id': '111',"
+ "'erporder_erpid' : '132',"
+ "'dtStart' : '10:00 12-12-12',"
+ "},"
+ "{"
+ "'id': '111',"
+ "'erporder_erpid' : '132',"
+ "'dtStart' : '10:00 12-12-12',"
+ "}]"
}
Objectclass.java
public class takeData {
public List<assignmentsData> assignments;
public List<assignmentsData> getAssignments() {
return assignments;
}
public void setAssignments(List<assignmentsData> assignments) {
this.assignments = assignments;
}
}
assignmentsData.java
public class assignmentsData {
public String id="";
public String erporder_erpid="";
public String dtStart="";
public String getId() {
return id;
}
public void setId(String id) {
this.id = id;
}
public String getErporder_erpid() {
return erporder_erpid;
}
public void setErporder_erpid(String erporder_erpid) {
this.erporder_erpid = erporder_erpid;
}
public String getDtStart() {
return dtStart;
}
public void setDtStart(String dtStart) {
this.dtStart = dtStart;
}
}
parsingClass.java
Gson mGson= new Gson();
Objectclass mObjectclass=gson.fromJson(jsonString, Objectclass.class);
访问: mObjectclass.getAssignments.get(0).getId();