我需要使用以下结构读取Java中的JSON文件:
{"id_user":"10","level":"medium","text":"hello 10"}
{"id_user":"20","level":"medium","text":"hello 20"}
{"id_user":"30","level":"medium","text":"hello 30"}
谢谢!
[POST-EDITED]
我有这个代码,但只读取第一个JSON对象,我需要逐个读取这三个对象。
private void loadJSONFile(){
FileReader fileReader = new FileReader(pathFile);
try (JsonReader jsonReader = new JsonReader(fileReader)) {
jsonReader.beginObject();
while (jsonReader.hasNext()) {
String name = jsonReader.nextName();
if (name.equals("filter_level")) {
System.out.println(jsonReader.nextString());
} else if (name.equals("text")) {
System.out.println("text: " + jsonReader.nextString());
} else {
jsonReader.skipValue();
}
}
jsonReader.endObject();
jsonReader.close();
}
}
谢谢!
答案 0 :(得分:6)
我知道这个帖子已经差不多一年了:)但我实际上再次作为答案重新发布,因为我有这个问题和袁一样
我有这个text.txt文件 - 我知道这不是一个有效的Json数组 - 但如果你看一下,你会发现这个文件的每一行都是一个Json对象。
{"Sensor_ID":"874233","Date":"Apr 29,2016 08:49:58 Info Log1"}
{"Sensor_ID":"34234","Date":"Apr 29,2016 08:49:58 Info Log12"}
{"Sensor_ID":"56785","Date":"Apr 29,2016 08:49:58 Info Log13"}
{"Sensor_ID":"235657","Date":"Apr 29,2016 08:49:58 Info Log14"}
{"Sensor_ID":"568678","Date":"Apr 29,2016 08:49:58 Info Log15"}
现在我想阅读上面的每一行,并将名称“Sensor_ID”和“Date”解析成Json格式。经过长时间的搜索,我有以下内容:
尝试并在控制台上查看结果。我希望它有所帮助。
package reading_file;
import java.io.*;
import java.util.ArrayList;
import org.json.simple.JSONObject;
import org.json.simple.parser.JSONParser;
import org.json.simple.parser.ParseException;
public class file_read {
public static void main(String [] args) {
ArrayList<JSONObject> json=new ArrayList<JSONObject>();
JSONObject obj;
// The name of the file to open.
String fileName = "C:\\Users\\aawad\\workspace\\kura_juno\\data_logger\\log\\Apr_28_2016\\test.txt ";
// This will reference one line at a time
String line = null;
try {
// FileReader reads text files in the default encoding.
FileReader fileReader = new FileReader(fileName);
// Always wrap FileReader in BufferedReader.
BufferedReader bufferedReader = new BufferedReader(fileReader);
while((line = bufferedReader.readLine()) != null) {
obj = (JSONObject) new JSONParser().parse(line);
json.add(obj);
System.out.println((String)obj.get("Sensor_ID")+":"+
(String)obj.get("Date"));
}
// Always close files.
bufferedReader.close();
}
catch(FileNotFoundException ex) {
System.out.println("Unable to open file '" + fileName + "'");
}
catch(IOException ex) {
System.out.println("Error reading file '" + fileName + "'");
// Or we could just do this:
// ex.printStackTrace();
} catch (ParseException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
}
答案 1 :(得分:3)
这是一个基于gson-2.8.0的工作示例(并经过测试)。它接受给定输入流上的任意序列的JSON对象。当然,它并没有对格式化输入的方式施加任何限制:
InputStream is = /* whatever */
Reader r = new InputStreamReader(is, "UTF-8");
Gson gson = new GsonBuilder().create();
JsonStreamParser p = new JsonStreamParser(r);
while (p.hasNext()) {
JsonElement e = p.next();
if (e.isJsonObject()) {
Map m = gson.fromJson(e, Map.class);
/* do something useful with JSON object .. */
}
/* handle other JSON data structures */
}
答案 2 :(得分:2)
我认为你的意思是你的Json字符串存储在一个文本文件中,你需要将它们读入Json对象。如果是这种情况,请使用BufferedReader或Scanner逐行读取文件,并使用json-simple将每行解析为Json对象
JsonReader用于读取一个Json对象。使用Scanner或BufferedReader逐行读取文件作为字符串,然后将其解析为Json Object.Here是一个示例
import org.json.simple.JSONObject;
import org.json.simple.parser.JSONParser;
import org.json.simple.parser.ParseException;
import java.io.File;
import java.io.FileNotFoundException;
import java.util.ArrayList;
import java.util.Scanner;
public class JSONExample{
public static void main(String x[]){
String FileName="C:\\Users\\Prasad\\Desktop\\JSONExample.txt";
try {
ArrayList<JSONObject> jsons=ReadJSON(new File(FileName),"UTF-8");
} catch (FileNotFoundException e) {
e.printStackTrace();
} catch (ParseException e) {
e.printStackTrace();
}
}
public static synchronized ArrayList<JSONObject> ReadJSON(File MyFile,String Encoding) throws FileNotFoundException, ParseException {
Scanner scn=new Scanner(MyFile,Encoding);
ArrayList<JSONObject> json=new ArrayList<JSONObject>();
//Reading and Parsing Strings to Json
while(scn.hasNext()){
JSONObject obj= (JSONObject) new JSONParser().parse(scn.nextLine());
json.add(obj);
}
//Here Printing Json Objects
for(JSONObject obj : json){
System.out.println((String)obj.get("id_user")+" : "+(String)obj.get("level")+" : "+(String)obj.get("text"));
}
return json;
}
}
答案 3 :(得分:1)
包括以下maven依赖:
<dependency>
<groupId>com.googlecode.json-simple</groupId>
<artifactId>json-simple</artifactId>
<version>1.1</version>
</dependency>
然后编写如下代码:
public class HistoricalData {
private static final String PATH = "<PATH>";
public static void main(String[] args) throws FileNotFoundException,
ParseException {
Scanner scanner = new Scanner(new File(PATH + "/Sample.txt"));
List<JSONObject> jsonArray = new ArrayList<JSONObject>();
while (scanner.hasNext()) {
JSONObject obj = (JSONObject) new JSONParser().parse(scanner.nextLine());
jsonArray.add(obj);
}
}
}
答案 4 :(得分:0)
我知道两个阅读JSON的选项。
JSON简单,它适用于小型JSON结果。 但GSON对于大json结果非常有用。因为您可以在GSON中设置Object表单。
第一次json.jar
用法:
String st = ""; // your json object to string
JSONObject newJson = null;
try {
newJson = new JSONObject(st);
newJson.getJSONObject("key");
} catch (JSONException e1) {
// TODO Auto-generated catch block
e1.printStackTrace();
}
第二个gson.jar
用法:
int one = gson.fromJson("1", int.class);
Integer one = gson.fromJson("1", Integer.class);
Long one = gson.fromJson("1", Long.class);
Boolean false = gson.fromJson("false", Boolean.class);
String str = gson.fromJson("\"abc\"", String.class);
String anotherStr = gson.fromJson("[\"abc\"]", String.class);
答案 5 :(得分:0)
通过此JSON文件的正确方法是:
"users": [
{
"id_user": "10",
"level": "medium",
"text": "hello 10"
},
{
"id_user": "20",
"level": "medium",
"text": "hello 20"
},
{
"id_user": "30",
"level": "medium",
"text": "hello 30"
}
]
如果您使用的是独立应用程序,请尝试使用XStream。它会在眨眼间将JSON解析为对象。
答案 6 :(得分:0)
我的数据格式为:
"array": [
{
"id": "1",
"name": "peter",
"text": "hie peter"
},
{
"id": "5",
"name": "rina",
"text": "hey rina"
},
{
"id": "12",
"name": "parx",
"text": "hey bro"
}
]
我试过这个并且它有效:
Object obj = parser.parse(new FileReader("/home/hp2/json.json"));
JSONObject jsonObject = (JSONObject) obj;
JSONArray array = (JSONArray) jsonObject.get("array"); // it should be any array name
Iterator<Object> iterator = array.iterator();
while (iterator.hasNext()) {
System.out.println("if iterator have next element " + iterator.next());
}
答案 7 :(得分:0)
将数据保存在[]中
[{"id_user":"10","level":"medium","text":"hello 10"}
{"id_user":"20","level":"medium","text":"hello 20"}
{"id_user":"30","level":"medium","text":"hello 30"}]
文件内部 这样它就变成了一个列表然后就可以使用JSONArray了。我写的方式如下
public class JSONReadFromFile {
@SuppressWarnings("unchecked")
public static void main(String[] args) {
JSONParser parser = new JSONParser();
try {
Object obj = parser.parse(new FileReader("\\D:\\JSON\\file3.txt"));
JSONArray jsonArray = (JSONArray) obj;
int length = jsonArray.size();
LinkedList author = new LinkedList();
for (int i =0; i< length; i++) {
JSONObject jsonObject = (JSONObject) jsonArray.get(i);
Set s = jsonObject.entrySet();
Iterator iter = s.iterator();
HashMap hm = new HashMap();
while(iter.hasNext()){
Map.Entry me = (Map.Entry) iter.next();
hm.put(me.getKey(), me.getValue());
}
author.add(hm);
}
for(int i=0;i<author.size();i++){
HashMap hm = (HashMap) author.get(i);
Set s = hm.entrySet();
Iterator iter = s.iterator();
while(iter.hasNext()){
Map.Entry me = (Map.Entry) iter.next();
System.out.println(me.getKey() + "---" + me.getValue());
}
} catch (Exception e) {
e.printStackTrace();
}
}
}
我得到的输出是
text---hello 10
id_user---10
level---medium
text---hello 20
id_user---20
level---medium
text---hello 30
id_user---30
level---medium
答案 8 :(得分:0)
我使用下面的代码并且工作正常。
public static void main(String[] args)
throws IOException, JSchException, SftpException, InterruptedException, ParseException
{
JSONParser parser = new JSONParser();
Object obj = parser.parse(new FileReader("c:\\netapp1.txt"));
Map<Object, Object> shareList = new HashMap<Object, Object>();
JSONObject jsonObject = (JSONObject) obj;
JSONArray array = (JSONArray) jsonObject.get("dataLevels"); // it should be any array name
Iterator<Object> iterator = array.iterator();
while (iterator.hasNext())
{
Object it = iterator.next();
JSONObject data = (JSONObject) it;
shareList.put(data.get("name"), data.get("type"));
}
Iterator it = shareList.entrySet().iterator();
while (it.hasNext())
{
Map.Entry value = (Map.Entry) it.next();
System.out.println("Name: " + value.getKey() + " and type: " + value.getValue());
}
}
JSON: {
"version": 1,
"dataLevels":
[
{
"name": "test1",
"externId": "test1",
"type": "test1"
},
{
"name": "test2",
"externId": "test2",
"type": "test2"
},
{
"name": "test3",
"externId": "test3",
"type": "test3"
}
}
答案 9 :(得分:0)
使用gson从流中读取多个对象。 使用gson-2.8.2,我不得不称之为:reader.setLenient(true);
JsonReader reader = new JsonReader(new InputStreamReader(is, "UTF-8"));
reader.setLenient(true);
while (true)
{
reader.beginObject();
while (reader.hasNext()) {
System.out.println("message: "+reader.nextName()+"="+reader.nextString());
}
System.out.println("=== End message ===");
reader.endObject();
这是由堆栈跟踪明确建议的,当我这样做时,代码运行得很好:
com.google.gson.stream.MalformedJsonException: Use JsonReader.setLenient(true) to accept malformed JSON at line 2 column 3481 path $
at com.google.gson.stream.JsonReader.syntaxError(JsonReader.java:1568)
at com.google.gson.stream.JsonReader.checkLenient(JsonReader.java:1409)
at com.google.gson.stream.JsonReader.doPeek(JsonReader.java:542)
at com.google.gson.stream.JsonReader.beginObject(JsonReader.java:379)
...