我有一个JSON响应,我想将每个元素存储在一个字符串中。因为我是JSON新手,所以很难找到解决方案。请给我建议一个解决方案。 以下是我的json响应。
{
"responseFlag": 1,
"responseMsg": "Successfully retrieved data",
"responseObj": [{
"assets": {
"asset_since": "",
"asset_type": "",
"comments": "",
"estimated_value": "",
"material_status": "SINGLE",
"ownership_of_assets": "",
"pep": "",
"source_of_income": ""
}
},
{
"assets": {
"asset_since": "",
"asset_type": "",
"comments": "",
"estimated_value": "",
"material_status": "SINGLE",
"ownership_of_assets": "",
"pep": "",
"source_of_income": ""
}
}
]
}
我想将每个对象元素存储在一个数组中。
我尝试过的代码如下。
package mytry;
import java.util.Iterator;
import org.json.simple.JSONArray;
import org.json.simple.JSONObject;
import org.json.simple.parser.JSONParser;
import org.json.simple.parser.ParseException;
public class Mytry {
public static void main(String[] args) {
// TODO code application logic here
String response="{\n" +
" \"responseFlag\": 1,\n" +
" \"responseMsg\": \"Successfully retrieved data\",\n" +
" \"responseObj\": [\n" +
" {\n" +
" \"assets\": {\n" +
" \"asset_since\": \"\",\n" +
" \"asset_type\": \"\",\n" +
" \"comments\": \"\",\n" +
" \"estimated_value\": \"\",\n" +
" \"material_status\": \"SINGLE\",\n" +
" \"ownership_of_assets\": \"\",\n" +
" \"pep\": \"\",\n" +
" \"source_of_income\": \"\"\n" +
" }},\n" +
" {\n" +
" \"assets\": {\n" +
" \"asset_since\": \"\",\n" +
" \"asset_type\": \"\",\n" +
" \"comments\": \"\",\n" +
" \"estimated_value\": \"\",\n" +
" \"material_status\": \"SINGLE\",\n" +
" \"ownership_of_assets\": \"\",\n" +
" \"pep\": \"\",\n" +
" \"source_of_income\": \"\"\n" +
" }}]}";
JSONParser parser = new JSONParser();
try {
Object obj = parser.parse(response);
JSONObject jsonObject = (JSONObject) obj;
//System.out.println(jsonObject.toString());
System.out.println("json size=="+jsonObject.size());
System.out.println("hghgfh"+jsonObject.keySet());
Long sflag = (Long) jsonObject.get("responseFlag");
String msg=(String) jsonObject.get("responseMsg");
String resobj=(String) jsonObject.get("responseObj").toString();
//jsonObject.
System.out.println("sflag=="+sflag);
System.out.println("msg=="+msg);
System.out.println("msg=="+resobj);
// JSONArray msg = (JSONArray) jsonObject.get("responseFlag");
// Iterator<String> iterator = msg.iterator();
// while (iterator.hasNext()) {
// System.out.println(iterator.next());
// }
// for(Iterator iterator = jsonObject.keySet().iterator(); iterator.hasNext();) {
// String key = (String) iterator.next();
// System.out.println(jsonObject.get(key));
//}
// String asset = (String) jsonObject.get("assets");
// System.out.println("session token"+asset);
//sflag = (Long) jsonObject.get("responseFlag");
//System.out.println("session sflag"+sflag);
} catch (ParseException ex) {
System.out.println(ex);
}
}
}
响应对象是
[{
"assets": {
"comments": "",
"asset_since": "",
"material_status": "SINGLE",
"source_of_income": "",
"ownership_of_assets": "",
"asset_type": "",
"pep": "",
"estimated_value": ""
}
}, {
"assets": {
"comments": "",
"asset_since": "",
"material_status": "SINGLE",
"source_of_income": "",
"ownership_of_assets": "",
"asset_type": "",
"pep": "",
"estimated_value": ""
}
}]
我需要将每个资产值存储在数组中。
答案 0 :(得分:2)
这是伪代码。您可以在此代码中填写缺少的部分。
String json = "{"responseFlag":1,"responseMsg":"Successfully retrieved data","responseObj":[{"assets":{"asset_since":"","asset_type":"","comments":"","estimated_value":"","material_status":"SINGLE","ownership_of_assets":"","pep":"","source_of_income":""}},{"assets":{"asset_since":"","asset_type":"","comments":"","estimated_value":"","material_status":"SINGLE","ownership_of_assets":"","pep":"","source_of_income":""}}]}";
JSONObject jsonObject = new JSONObject(json);
JSONArray jsonArray = jsonObject.getJSONArray("responseObj");
for(int i=0; i<jsonArray.length(); i++)
{
JSONObject arrayJsonObject = jsonArray.getJSONObject(i);
//insert into your list or array
}
答案 1 :(得分:1)
如果您使用的是json-simple-1.1.1 jar。这是下面的代码:
JSONParser parser = new JSONParser();
try {
Object obj = parser.parse(response);
JSONObject jsonObject = (JSONObject) obj;
//System.out.println(jsonObject.toString());
System.out.println("json size==" + jsonObject.size());
System.out.println("hghgfh" + jsonObject.keySet());
JSONArray jsonArray = (JSONArray)jsonObject.get("responseObj");
for(int i=0; i<jsonArray.size(); i++)
{
JSONObject arrayJsonObject = (JSONObject) jsonArray.get(i);
JSONObject assets = (JSONObject) arrayJsonObject.get("assets");
// read the assets to store
}
}catch (Exception e){
}