将查询限制为查询的5个最低值，为变量的5个最低值

Question

我想将下面的查询限制为5个结果。但不只是任何5个结果。 points的5个最低值。我怎么能这样做？

$side = "SELECT title, points, submissionid
             FROM submission 
            WHERE points >= '$sidepoints' 
         ORDER BY points DESC"; 

编辑：我希望按points降序排列结果。

Answer 1

在MySQL中：

$side = "SELECT title, points, submissionid
         FROM submission 
         WHERE points >= '$sidepoints' 
         ORDER BY points ASC
         LIMIT 5";

修改

您可以将以上查询与以下PHP代码一起使用，或使用其他SQL查询。

PHP反向结果（未经测试）

$q = mysql_query($side);
$results = array();
while($r = mysql_fetch_assoc($q))
{
    $results[] = $r;
}
$results = array_reverse($results);
foreach($results as $result)
{
    echo $result['points']; // etc
}

或SQL方式（未经测试 - 从this post找到）

SELECT title, points, submissionid 
FROM (
    SELECT title, points, submissionid
         FROM submission 
         WHERE points >= '$sidepoints' 
         ORDER BY points ASC
         LIMIT 5
) AS t1 ORDER BY points DESC

Answer 2

尝试使用其他查询（子查询）

来订购查询结果

SELECT * FROM (
  SELECT title, points, submissionid
  FROM submission 
  WHERE points >= '$sidepoints' 
  ORDER BY points ASC
  LIMIT 5
) t ORDER BY t.points DESC

Answer 3

如果您使用MYSQL，请使用LIMIT。

$side = "SELECT title, points, submissionid
         FROM submission 
         WHERE points >= '$sidepoints' 
         ORDER BY points DESC
         LIMIT 5"; 

ansi sql使用TOP。这适用于sql server

 $side = "SELECT TOP 5 title, points, submissionid
             FROM submission 
             WHERE points >= '$sidepoints' 
             ORDER BY points DESC"; 

Answer 4

SELECT ... ORDER BY points ASC LIMIT 5？