Question

我有4张桌子，最后一张给我带来麻烦。我希望即使不在我选择的日期，也会出现该id（Tanque）的最后结果。我正在使用sql manager studio 2008

表CB-LA_Sondagens有：

[CodTurnoAuto]
,[CodAbast]
,[Tanque]
,[PSSID]
,[SondagemEfect]

表CB_CFG_Tanques包含：

[Codigo]
,[PSSID]
,[Descricao]

这是查询：

SELECT 
     CC.[PssID]
    ,(SELECT Descricao FROM FGER_Armazens (nolock) as FGA WHERE FGA.Codigo = CC.Armazem) as Armazem
    ,T.Combustivel
    ,T.Descricao
    ,T.Ma_  as Capacidade
    ,cast(SOND.SondagemEfect as int) as Sondagem
    ,CBA.Data
FROM [MXPETROL_AB].[dbo].[Config_Comunicacoes] (nolock) as CC
LEFT JOIN [CB_CFG_Tanques] (nolock) as T ON T.PSSID = CC.PssID
LEFT JOIN CB_LA_Sondagens (nolock) as sond ON T.PSSID=sond.pssid and T.Codigo=sond.tanque
LEFT JOIN CB_Abastecimentos (nolock) as CBA ON CBA.CodTurnoAuto=sond.CodTurnoAuto and CBA.CodAbast=sond.CodAbast
WHERE TipoExportacao in (0,1) and CC.PSSID = '509' and CBA.Data>='2016-11-14 00:00:00' and CBA.Data<='2016-11-15 00:00:00' 
GROUP BY T.Combustivel,Armazem, CC.PSSID,  T.Descricao, T.Ma_, SondagemEfect, CBA.Data

我得到了什么：

我希望桌子的其余部分“Tanque”拥有CB_LA_Sondagens（SondagemEffect）中的最后一条记录。如你所见，我应该有7条记录，但我只有4条记录

Answer 1

SELECT
    PSS, Armazem, Descr,Combustivel, cap, (CASE WHEN sondagemfinal = NULL THEN NULL ELSE MAX(Sondagemfinal) END) as sondagem, (CASE WHEN datafinal = NULL THEN NULL ELSE MAX(datafinal) END) as data
FROM(
    SELECT PSS, Armazem,Descr, MAX(capacidade) as cap, (CASE WHEN dataa > 0 THEN MAX(Sondagem) ELSE NULL END) as SondagemFinal, MAX(dataa) as datafinal, Combustivel
    FROM(
        SELECT 
                CC.[PssID] as Pss
            ,(SELECT Descricao FROM FGER_Armazens (nolock) as FGA WHERE FGA.Codigo = CC.Armazem) as Armazem
            ,T.Descricao as descr
            ,T.Ma_  as Capacidade
            ,(SELECT top 1 cast(SondagemFinal as int) from CB_LA_Sondagens (nolock) as CLA INNER JOIN CB_Abastecimentos as CB ON CB.CodTurnoAuto = CLA.CodTurnoAuto AND CB.CodAbast = CLA.CodAbast
                where CLA.PSSID = CC.PssID and CLA.Tanque = SOND.Tanque and CB.Data <= '2016-11-15 00:00:00' 
                order by data desc) as sondagem
            ,CBA.Data as dataa
            ,(select Descricao from CB_CFG_Combustiveis as comb where comb.codigo in (
             (select combustivel from CB_CFG_Tanques as tanq where tanq.pssid=CC.pssid and tanq.codigo=sond.tanque))) as Combustivel
        FROM [MXPETROL_AB].[dbo].[Config_Comunicacoes] (nolock) as CC
        INNER JOIN [CB_CFG_Tanques] (nolock) as T ON T.PSSID = CC.PssID
        INNER JOIN CB_LA_Sondagens (nolock) as sond ON T.PSSID=sond.pssid and T.Codigo=sond.tanque
        LEFT JOIN CB_Abastecimentos (nolock) as CBA ON (CBA.CodTurnoAuto=sond.CodTurnoAuto 
                                                        AND CBA.CodAbast=sond.CodAbast) 
                                                        AND CBA.Data>='2016-11-14 00:00:00'
                                                        AND CBA.Data<='2016-11-15 00:00:00' 
        WHERE TipoExportacao in (0,1) and CC.Armazem = '509' 
        GROUP BY Armazem, CC.PSSID,  T.Descricao, T.Ma_, SondagemFinal, CBA.Data, sond.tanque
    )Res
    GROUP BY PSS, Armazem, Descr, dataa, Combustivel
)res
GROUP BY PSS, Armazem, Descr, cap,Combustivel
ORDER BY Armazem ASC, Combustivel

SQL Query限制其余值

1 个答案: