是否可以使用PHP Relative Date Time format获取一周的第一个/最后一个日期?
我试过:
date_default_timezone_set('Europe/Amsterdam');
$date = new DateTime();
$date->modify('first day of this week'); // to get the current week's first date
echo $date->format('Y-m-d'); // outputs 2011-12-19
$date->modify('first day of week 50'); // to get the first date of any week by weeknumber
echo $date->format('Y-m-d'); // outputs 2011-12-18
$date->modify('last day of this week'); // to get the current week's last date
echo $date->format('Y-m-d'); // outputs 2011-12-17
$date->modify('last day of week 50'); // to get the last date of any week by weeknumber
echo $date->format('Y-m-d'); // outputs 2011-12-18
尽可能see它不会输出正确的日期。
根据the docs,如果我是正确的,这应该是可能的。
我做错了什么?
修改
我需要在远期使用PHP的DateTime作为日期。
更新
现在变得更加陌生。我做了一些测试。
Windows PHP 5.3.3
2011-12-01
Warning: DateTime::modify() [datetime.modify]: Failed to parse time string (first day of week 50) at position 13 (w): The timezone could not be found in the database in C:\Users\Gerrie\Desktop\ph\Websites\Charts\www.charts.com\public\index.php on line 9
2011-12-01
2011-11-30
Warning: DateTime::modify() [datetime.modify]: Failed to parse time string (last day of week 50) at position 12 (w): The timezone could not be found in the database in C:\Users\Gerrie\Desktop\ph\Websites\Charts\www.charts.com\public\index.php on line 15
2011-11-30
Linux 5.3.8
2011-12-01
2011-12-01
2011-11-30
2011-11-30
答案 0 :(得分:42)
我是使用Carbon库的忠实粉丝,这使得这类事情变得非常简单。例如:
use Carbon\Carbon;
$monday = Carbon::now()->startOfWeek()
$sunday = Carbon::now()->endOfWeek()
或者,如果您希望将星期日作为一周的第一天:
use Carbon\Carbon;
Carbon::setWeekStartsAt(Carbon::SUNDAY);
Carbon::setWeekEndsAt(Carbon::SATURDAY);
$sunday = Carbon::now()->startOfWeek()
$saturday = Carbon::now()->endOfWeek()
答案 1 :(得分:25)
根据文档,格式字符串“第一天”和“最后一天”仅允许数月,而不是数周。见http://www.php.net/manual/en/datetime.formats.relative.php
如果将第一天和最后一天与周语句结合使用,结果要么会破坏解析器,要么是您没想到的(通常是一个月的第一天或最后一天,而不是一周)。
您在Win和Linux之间看到的差异可能仅仅是因为不同的错误报告设置。
要获取本周的第一天和最后一天,请使用:
$date->modify('this week');
$date->modify('this week +6 days');
要获得第50周的第一天和最后一天:
$date->setISODate(2011, 50);
$date->setISODate(2011, 50, 7);
修改强>
如果要对绝对周数使用修改方法,则必须使用http://www.php.net/manual/en/datetime.formats.compound.php中定义的格式:
$date->modify('2011W50');
$date->modify('2011W50 +6 days');
答案 2 :(得分:3)
如果一周的第一天是星期一
$date->modify('Monday this week');
否则,如果第一天是星期天
$date->modify('Sunday this week');
因为在不同国家/地区的第一天可能是周一或周日
答案 3 :(得分:2)
这是我用来从任何日期获取本周的第一天和最后一天的内容。 在这种情况下,星期一是一周的第一天......
$date = date('Y-m-d'); // you can put any date you want
$nbDay = date('N', strtotime($date));
$monday = new DateTime($date);
$sunday = new DateTime($date);
$monday->modify('-'.($nbDay-1).' days');
$sunday->modify('+'.(7-$nbDay).' days');
答案 4 :(得分:0)
function getweek_first_last_date($date)
{
$cur_date = strtotime($date); // Change to whatever date you need
// Get the day of the week: Sunday = 0 to Saturday = 6
$dotw = date('w', $cur_date);
if($dotw>1)
{
$pre_monday = $cur_date-(($dotw-1)*24*60*60);
$next_sunday = $cur_date+((7-$dotw)*24*60*60);
}
else if($dotw==1)
{
$pre_monday = $cur_date;
$next_sunday = $cur_date+((7-$dotw)*24*60*60);
}
else if($dotw==0)
{
$pre_monday =$cur_date -(6*24*60*60);;
$next_sunday = $cur_date;
}
$date_array = array();
$date_array['start_date_of_week'] = $pre_monday;
$date_array['end_date_of_week'] = $next_sunday;
return $date_array;
}
$date = '2013-12-22';
getweek_first_last_date($date);
Output :
$array_of_week = Array
(
[start_date_of_week] => 1387152000
[end_date_of_week] => 1387670400
)
$start_date =date('d/m/Y', $array_of_week['start_date_of_week'])
答案 5 :(得分:0)
<code>
function getlastweek_first_last_date()
{
$cur_date = strtotime(date('Y-m-d')); // Change to whatever date you need
// Get the day of the week: Sunday = 0 to Saturday = 6
$previousweekcurdate = $cur_date - (7*24*3600);
$cur_date = $previousweekcurdate;
$dotw = date('w', $cur_date);
if($dotw>1)
{
$pre_sunday = $cur_date-(($dotw-1)*24*60*60) - (24*60*60);
$next_satday = $cur_date+((7-$dotw)*24*60*60)- (24*60*60);
}
else if($dotw==1)
{
$pre_sunday = $cur_date- (24*60*60);
$next_satday = $cur_date+((7-$dotw)*24*60*60)- (24*60*60);
}
else if($dotw==0)
{
$pre_sunday =$cur_date -(6*24*60*60)- (24*60*60);
$next_satday = $cur_date- (24*60*60);
}
$pre_sunday = date('Y-m-d',$pre_sunday)." 00:00:00";
$next_satday = date('Y-m-d',$next_satday)." 23:59:59";
$date_array = array();
$date_array['sdoflw'] = $pre_sunday;
$date_array['edoflw'] = $next_satday;
return $date_array;
}
$date_array = getlastweek_first_last_date();
echo $start_date_of_week = $date_array['sdoflw'];
echo $end_date_of_week = $date_array['edoflw'];
</code>