如何在python中计算星期的第一个星期和最后一个星期

Question

我需要在python中计算一周的日期

我需要这个

year = 2012
week = 23
(a,b) = func (year,week)
print a
print b

>>>2012-04-06
>>>2012-06-10

你能帮帮我吗？

Answer 1

日期对象包含weekday()方法。

星期日6日为星期六返回0。

（来自谷歌搜索）这里有一个解决方案：http://www.protocolostomy.com/2010/07/06/python-date-manipulation/）

我认为这可以减少冗长，所以这是我的抨击：

def week_magic(day):
    day_of_week = day.weekday()

    to_beginning_of_week = datetime.timedelta(days=day_of_week)
    beginning_of_week = day - to_beginning_of_week

    to_end_of_week = datetime.timedelta(days=6 - day_of_week)
    end_of_week = day + to_end_of_week

    return (beginning_of_week, end_of_week)

Answer 2

很少有过时的答案，但有一个名为isoweek的好模块真的可以完成。要回答原始问题，您可以执行以下操作：

from isoweek import Week    

week = Week(2012, 23)
print(week.monday())
print(week.sunday())

希望这有助于任何人。

Answer 3

我认为@Anthony Sottile的答案应该是这样的：

def week_magic(day):
    day_of_week = day.weekday()

    to_beginning_of_week = datetime.timedelta(days=day_of_week)
    beginning_of_week = day - to_beginning_of_week

    to_end_of_week = datetime.timedelta(days=6 - day_of_week)
    end_of_week = day + to_end_of_week

    return (beginning_of_week, end_of_week)

有效！