我有一张员工表,显示员工编号,姓名和经理的员工编号。我正在尝试创建一个显示emp名称,emp#,manager name和mgr#的查询。
表格如下:
EMPNO ENAME JOB MGR HIREDATE SAL COMM DEPTNO
7839 KING PRESIDENT - 17-NOV-81 5000 - 10
7698 BLAKE MANAGER 7839 01-MAY-81 2850 - 30
7782 CLARK MANAGER 7839 09-JUN-81 2450 - 10
7566 JONES MANAGER 7839 02-APR-81 2975 - 20
7654 MARTIN SALESMAN 7698 28-SEP-81 1250 1400 30
7499 ALLEN SALESMAN 7698 20-FEB-81 1600 300 30
7844 TURNER SALESMAN 7698 08-SEP-81 1500 0 30
7900 JAMES CLERK 7698 03-DEC-81 950 - 30
7521 WARD SALESMAN 7698 22-FEB-81 1250 500 30
7902 FORD ANALYST 7566 03-DEC-81 3000 - 20
其中三列非常简单,因为它们在表格中,但是如果我拥有的是经理的员工编号,我将如何添加经理名称?
这是我到目前为止只显示3个列的
select ename as "Employee", empno as "Emp#", mgr as "Mgr#" from emp;
任何帮助将不胜感激
答案 0 :(得分:9)
select
emp.ename as "Employee",
emp.empno as "Emp#",
emp.mgr as "Mgr#",
m.ename as "Manager"
from
emp
LEFT OUTER JOIN emp m ON
emp.mgr = m.empno
答案 1 :(得分:4)
试试这个:
select e.ename ,e.sal, (select s.grade from salgrade s where e.sal between s.losal and s.hisal) empgrade ,e2.ename"mgr", e2.sal mgrsal,
(select s.grade from salgrade s where e2.sal between s.losal and s.hisal) mgrgrade from emp e,emp e2
where e.mgr=e2.empno(+)
答案 2 :(得分:2)
select
e.ename as "Employee",
e.empno as "Emp#",
e.mgr as "Mgr#",
m.ename as "MgrName"
from emp e
join emp m on e.mgr = m.empno
答案 3 :(得分:1)
SELECT DISTINCT E.ENAME,E.job
FROM EMP E
JOIN EMP Y
ON E.EMPNO=Y.MGR;
这将为您提供作为经理的独特员工姓名。
或者:
SELECT E.ENAME,E.job
FROM EMP E
JOIN EMP Y
ON E.EMPNO=Y.MGR;
或者:
SELECT E.ENAME,E.job
FROM EMP E, EMP Y
WHERE
E.EMPNO=Y.MGR;
答案 4 :(得分:1)
select e.ename as "Employee", e.empno as "Emp#", e.mgr as "Mgr#", m.ename as "MgrName" from emp e , emp m on e.mgr = m.empno
答案 5 :(得分:1)
尝试此查询
SELECT E2.EMPID,E2.EMPNAME,E1.EMPNAME
AS MGRNAME
FROM employee E1
INNER JOIN employee E2 ON E1.Empid=E2.ManagerId
答案 6 :(得分:0)
SELECT (CASE
WHEN e1.manager_id IS NULL THEN
e1.last_name ||' IS THE PRESIDENT'
ELSE
e2.last_name || ' IS THE MANAGER OF '||e1.last_name
END)"HIERARCHY" FROM hr.employees e1, hr.employees e2 WHERE e1.manager_id = e2.employee_id(+) ORDER BY e1.manager_id NULLS FIRST
答案 7 :(得分:0)
我试过它工作正常。
SELECT a.empno EmpID,a.empname EmpName, a.mgrid MgrID,(select empname from employee where empno = a.mgrid) MgrName
from employee a, employee b
where a.empno = b.empno order by a.empno asc;
答案 8 :(得分:-1)
Select e.ename empname , m.ename managername,e.empno empno ,m.mgr managerno from emp e, mgr m
where m.empno=e.mgr