Question

我有员工表

EMPID  | EMPNAME    
1      | A        
2      | B

我有[经理表]

MNGID  | EMPID    
2      | 1

以上MNGID指员工表表示B是A的经理。

我想查询显示管理员名称和员工姓名。请注意结果

Answer 1

这应该适合你：

class my_tasks(models.Model):
_inherit ='project.task'
identify_manager   = fields.Boolean(compute='check_user')

@api.model
def check_user(self):
    data = {}
    # search current user id
    user_id = self.env['res.users'].search([('id', '=', self.env.user.id)])
    # search the module category which called as My module
    user_my_category_id = self.env['ir.module.category'].search([('name', '=', 'My Module')])
    # search the manager id which belongs to my module category
    user_new_id = self.env['res.groups'].search(
        [('category_id', '=', user_my_category_id.id), ('name', '=', "Manager")]).id

    # search using count whether the current user has a role of manager for my project module
    query = """select COUNT(*) from res_groups_users_rel where uid=%d and gid=%d """ % (user_id.id, user_tiq_id)
    self.env.cr.execute(query)
    result = self.env.cr.fetchall()

    # convert the  string count into a integer
    json_result = json.dumps(result, ensure_ascii=False)
    count = json_result.strip('\' \" [] ')
    str_count = str(count)
    int_count = int(str_count)
    if int_count != 0:
        self.identify_manager = True
    else:
        self.identify_manager = False

Answer 2

试试这个[更新的查询]：

SELECT 
    m1.empname as manager,
    e.empname as employee
FROM
    Manager m
JOIN
    Employee e
ON
    m.empid = e.empid
JOIN
    Employee m1
ON
    m1.empid = m.mngid

=====

http://www.sqlfiddle.com/#!9/61560b/1

员工表和经理表

2 个答案: