Question

我无法弄清楚为什么current_user总是设置为user_id = 1。

当它编辑数据时，它会适当地设置user_id，但是当它创建新记录时，它会设置user_id = 1

使用rails 3.1.3 w / Devise

控制器：

def update_multiple

@user = current_user
for @workoutdate in params[:workout_workoutdates]
  is_new = false

  #this part works, user_id ends up equaling the current_user

  @workouts = Workout.where(:user_id => @user, 
                            :workoutdate => @workoutdate.to_time)
  if !@workouts.any?

    # when setting user_id to an integer it works
    # for example, workout = Workout.new(:user_id => 3), it works

    workout = Workout.new(:user_id => @user, 
                          :workoutdate => @workoutdate.to_time)
    is_new = true
  else
    workout = @workouts[0]
  end
  workout.save
end

终端产生的SQL：

SQL (0.7ms)  INSERT INTO "intervals" ("created_at", "interval_name", "updated_at", "workout_id") VALUES (?, ?, ?, ?)  [["created_at", Tue, 13 Dec 2011 03:24:28 UTC +00:00], ["interval_name", "INTERVAL"], ["updated_at", Tue, 13 Dec 2011 03:24:28 UTC +00:00], ["workout_id", nil]]

SQL (0.5ms)  INSERT INTO "workouts" ("created_at", "updated_at", "user_id", "workoutdate") VALUES (?, ?, ?, ?)  [["created_at", Tue, 13 Dec 2011 03:24:28 UTC +00:00], ["updated_at", Tue, 13 Dec 2011 03:24:28 UTC +00:00], ["user_id", 1], ["workoutdate", Thu, 08 Dec 2011 08:00:00 UTC +00:00]]

Answer 1

我使用不同的设计。我觉得你太难了。使用devise，您可以像这样引用用户对象（锻炼）：

@workouts = current_user.workouts.find(...)

然后像这样创建一个新的：

@workout = current_user.workout.build(...)

依此类推......

为什么current_user总是user_id = 1？

1 个答案: