我在2D空间中有一个点矢量,例如:
[[0 0] [1 1] [2 2]]
需要计算某个点与向量中每个点之间的距离,以确定向量中的哪个点最接近我正在查询的点。我需要知道距离和最近点,所以我想要一个像这样的哈希矢量:
[{:point [0 0] :dist 2.7} {:point [1 1] :dist 3.5} {:point [2 2] :dist 4.3}]
如何将前者转变为后者?我试过这样的事情:
(defn closest-point [point all-points]
(map #({:point % :dist (distance point %)}) all-points))
但是我收到了一个错误:
(user=> ArityException Wrong number of args (0) passed to: PersistentArrayMap clojure.lang.AFn.throwArity (AFn.java:437)
答案 0 :(得分:9)
#({...})
扩展为(fn [] ({....}))
,试图在没有任何参数的情况下调用地图。
试试这个:
(defn closest-point [point all-points]
(map (fn [p] {:point p :dist (distance point p)}) all-points))
或
(defn closest-point [point all-points]
(map #(hash-map :point % :dist (distance point %)) all-points))
或
(defn dist-info
[point p]
{:point p :dist (distance point p)})
(defn closest-point [point all-points]
(map #(dist-info point %) all-points))
答案 1 :(得分:5)
如果您使用for
理解而不是map
,则更具可读性。另外,要实际选择最近的点,您可以使用min-key
:
(defn closest-point [point all-points]
(apply min-key :dist
(for [p all-points]
{:point p :dist (distance point p)})))
答案 2 :(得分:2)
如果要修改它而不从代码中删除任何内容,只需添加一个单词:identity
(defn closest-point [point all-points]
(map #(identity {:point % :dist (distance point %)}) all-points))
答案 3 :(得分:1)
(defn closest-point [point all-points]
(map #(hash-map :point % :dist (distance point %) ) all-points)
结果: -
({:point [0 0], :dist 2.7} {:point [1 1], :dist 3.5} {:point [2 2], :dist 4})