Question

我想找到Top和botton 10％的销售人员。我怎么能用SQL 2005或2008做到这一点？

DECLARE @Sales TABLE 
(
SalesPersonID varchar(10), TotalSales int
)


INSERT @Sales
SELECT 1, 200 UNION ALL
SELECT 2, 300 UNION ALL
SELECT 7, 300 UNION ALL
SELECT 4, 100 UNION ALL
SELECT 5, 600 UNION ALL
SELECT 5, 600 UNION ALL
SELECT 2, 200 UNION ALL
SELECT 5, 620 UNION ALL
SELECT 4, 611 UNION ALL
SELECT 3, 650 UNION ALL
SELECT 7, 611 UNION ALL
SELECT 9, 650 UNION ALL
SELECT 3, 555 UNION ALL
SELECT 9, 755 UNION ALL
SELECT 8, 650 UNION ALL
SELECT 3, 620 UNION ALL
SELECT 5, 633 UNION ALL
SELECT 6, 720 
GO

此外，如果我添加部门，那么我如何编写相同的查询来查找每个部门的前10％和后10％？我想要两个查询。

Answer 1

TOP 10％

select top 10 percent SalesPersonID, sum(TotalSales)
  from Sales
 order by sum(TotalSales)
 group by SalesPersonID

底部10％

select top 10 percent SalesPersonID, sum(TotalSales)
  from Sales
 order by sum(TotalSales) desc
 group by SalesPersonID

Answer 2

--Top 10%
SELECT TOP 10 PERCENT SalesPersonID, SUM(TotalSales) FROM @Sales
GROUP BY SalesPersonID
ORDER BY SUM(TotalSales) ASC

--Bottom 10%
SELECT TOP 10 PERCENT SalesPersonID, SUM(TotalSales) FROM @Sales
GROUP BY SalesPersonID
ORDER BY SUM(TotalSales) DESC

如果您添加了一个列Department varchar（20），例如：

--By Dept
SELECT TOP 10 PERCENT Department, SUM(TotalSales) FROM @Sales
GROUP BY Department
ORDER BY SUM(TotalSales) ASC/DESC //(Whichever one you want)

Answer 3

cte版本：

DECLARE @Sales TABLE (SalesPersonID varchar(10), TotalSales int)INSERT @Sales
SELECT 1, 200 UNION ALL
SELECT 2, 300 UNION ALL
SELECT 7, 300 UNION ALL
SELECT 4, 100 UNION ALL
SELECT 5, 600 UNION ALL
SELECT 5, 600 UNION ALL
SELECT 2, 200 UNION ALL
SELECT 5, 620 UNION ALL
SELECT 4, 611 UNION ALL
SELECT 3, 650 UNION ALL
SELECT 7, 611 UNION ALL
SELECT 9, 650 UNION ALL
SELECT 3, 555 UNION ALL
SELECT 9, 755 UNION ALL
SELECT 8, 650 UNION ALL
SELECT 3, 620 UNION ALL
SELECT 5, 633 UNION ALL
SELECT 6, 720 


;with a as
(
    select SalesPersonID, sum(TotalSales) as Total
    from @Sales
    group by SalesPersonID
)
select coalesce(a.SalesPersonID, b.SalesPersonID) as SalesPersonID, coalesce(a.Total,b.Total) as Total
from a a
    full outer join a b
        on a.SalesPersonID=b.SalesPersonID
where a.SalesPersonID in (select top 10 percent SalesPersonID from a order by Total desc)
    or b.SalesPersonID in (select top 10 percent SalesPersonID from a order by Total)
order by a.Total desc

找到顶级销售人员

3 个答案: