我正在尝试实现一个客户端服务器应用程序
服务器程序有一个计数器,根据请求递增1(没有提供给客户端的计数器值可以复制)
客户端程序要求服务器程序递增计数器并获得递增值
服务器程序应该能够一次处理多个客户端(至少5个)
计数器值应该由所有服务器线程共享,如果有的话
我已经在单独的项目中实现了服务器和客户端应用程序。当我开始运行服务器然后客户端时,服务器程序跟随行会产生NullReferanceException。
NetworkStream netstream = ((TcpClient)client).GetStream();
我是C#的新手。我想知道客户端如何连接到服务器并获得递增的值。
我在这里附上了我的代码。
提前致谢。
MyServer.cs
public abstract class MyServer
{
private static int port = 8080;
private static TcpListener listener;
private static Thread thread;
private static int clientId = 0;
static void Main(string[] args)
{
listener = new TcpListener(new IPAddress(new byte[] {127,0,0,1}),port);
thread = new Thread(new ThreadStart(Listen));
thread.Start();
}
private static void Listen()
{
listener.Start();
Console.WriteLine("Listening on: " + port.ToString());
while(true)
{
Console.WriteLine("Waiting for connection....");
Console.WriteLine("Client No: " + clientId);
TcpClient client = listener.AcceptTcpClient();
Thread listenThread = new Thread(new ParameterizedThreadStart(ListenThread));
listenThread.Start();
}
}
private static void ListenThread(Object client)
{
NetworkStream netstream = ((TcpClient)client).GetStream();
Console.WriteLine("Request made");
clientId = clientId + 1;
// String message = "Hello world";
byte[] resMessage = Encoding.ASCII.GetBytes(clientId.ToString());
netstream.Write(resMessage, 0, resMessage.Length);
netstream.Close();
}
}
MyClient.cs
class MyClient
{
static void Main(string[] args)
{
TcpClient tcpClient;
int port = 8080;
NetworkStream stream = null;
tcpClient = new TcpClient("127.0.0.1", port);
Console.WriteLine("Connection was established....");
stream = tcpClient.GetStream();
Byte[] response = new Byte[tcpClient.ReceiveBufferSize];
stream.Read(response,0,(int)tcpClient.ReceiveBufferSize);
String returnData = Encoding.UTF8.GetString(response);
Console.WriteLine("Server Response " + returnData);
tcpClient.Close();
stream.Close();
}
}
答案 0 :(得分:3)
你正在启动没有参数的线程,而它期望一个(客户端的TcpStream
)。改变这个:
listenThread.Start();
到此:
listenThread.Start(client);
顺便说一句,我称之为clientThread
而不是listenThread
;线程没有收听,它正在关注客户端。