是否可以在c#中以字母数字的形式对任意属性进行通用列表排序?如果问题不明确,请告诉我,我会想出一个例子。
提前致谢
注意:我发现这个链接可以做到但不是按字母顺序排列的。谁能帮我吗? http://blog.codewrench.net/2009/04/14/sorting-a-generic-list-on-arbitrary-property/
答案 0 :(得分:1)
这是一个快速的字母数字排序(也可以用于其他种类的数字)。
C#字母数字排序http://www.dotnetperls.com/alphanumeric-sorting
public class AlphanumComparatorFast : IComparer
{
public int Compare(object x, object y)
{
string s1 = x as string;
if (s1 == null)
{
return 0;
}
string s2 = y as string;
if (s2 == null)
{
return 0;
}
int len1 = s1.Length;
int len2 = s2.Length;
int marker1 = 0;
int marker2 = 0;
// Walk through two the strings with two markers.
while (marker1 < len1 && marker2 < len2)
{
char ch1 = s1[marker1];
char ch2 = s2[marker2];
// Some buffers we can build up characters in for each chunk.
char[] space1 = new char[len1];
int loc1 = 0;
char[] space2 = new char[len2];
int loc2 = 0;
// Walk through all following characters that are digits or
// characters in BOTH strings starting at the appropriate marker.
// Collect char arrays.
do
{
space1[loc1++] = ch1;
marker1++;
if (marker1 < len1)
{
ch1 = s1[marker1];
}
else
{
break;
}
} while (char.IsDigit(ch1) == char.IsDigit(space1[0]));
do
{
space2[loc2++] = ch2;
marker2++;
if (marker2 < len2)
{
ch2 = s2[marker2];
}
else
{
break;
}
} while (char.IsDigit(ch2) == char.IsDigit(space2[0]));
// If we have collected numbers, compare them numerically.
// Otherwise, if we have strings, compare them alphabetically.
string str1 = new string(space1);
string str2 = new string(space2);
int result;
if (char.IsDigit(space1[0]) && char.IsDigit(space2[0]))
{
int thisNumericChunk = int.Parse(str1);
int thatNumericChunk = int.Parse(str2);
result = thisNumericChunk.CompareTo(thatNumericChunk);
}
else
{
result = str1.CompareTo(str2);
}
if (result != 0)
{
return result;
}
}
return len1 - len2;
}
}
使用
var unordered = new[] { "100F", "50F", "SR100", "SR9" };
var ordered = unordered.OrderBy(s => s, new AlphanumComparatorFast());
这是一篇关于这个问题的好文章:
为人类排序:自然排序顺序http://www.codinghorror.com/blog/2007/12/sorting-for-humans-natural-sort-order.html
答案 1 :(得分:0)