Question

我正在使用python 2.7而我正在尝试读取文件夹中的文件名，并按照令人憎恶的顺序排序。

我的代码是：

filenamelist=[]
txt_path = 'decoded'

for filename in sorted(os.listdir(txt_path)):
  with open(txt_path+"/"+filename) as myfile:
    for line in myfile:
        if "Total Time" in line:

            filenamelist.append(filename)

当我打印filenamelist时，我得到以下内容：

[＆＃39; pirkagia_10b_lowdelay_P_192x144_Filters_OFF_ level_0 _192x144_15_50_dec.txt＆＃39;，＆＃39; p irkagia_10b_lowdelay_P_192x144_Filters_OFF_的 level_10 _192x144_25_42_dec.txt＆＃39 ;,＆＃39; pirkagia_10b_lowdelay_P_192x144_Filters_OFF_的 level_11 _192x144_25_38_dec.txt＆＃39 ;,＆＃39; pirkagia_10b_lowdelay_P_192x144_Filters_OFF_level_12_192x144_25_34_dec.txt＆＃39;，＆＃39 ; pirkagia_10b_lowdelay_P_192x144_Filters_OFF_level_13_192x144_25_30_dec.txt＆＃39 ;,＆＃39; pirkagia_10b_lowdelay_P_192x144_Filters_OFF_level_14_192x144_25_26_dec.txt＆＃39 ;,＆＃39; pirkagia_10b_lowdelay_P_192x144_Filters_OFF_level_15_192x144_25_22_dec.txt＆＃39 ;,＆＃39; pirkagia_10b_lowdelay_P_192x144_Filters_OFF_level_1_192x144_15_46_dec.txt＆＃39 ;,＆＃39; pirkagia_10b_lowdelay_P_192x144_Filters_OFF_level_2_192x144_15_42_dec.txt＆＃39 ;，＆＃39; pirkagia_10b_lowdelay_P_192x144_Filters_OFF_level_3_192x144_15_38_dec.txt＆＃39;，＆＃39; pirkagia_10b_lowdelay_P_192x144_Filters_OFF_level_4_192x144_15_34_dec.txt＆＃39;，...]

可以看出，这没有排序。我想获得level_0, level_1, level_2, ..., level_9, level_10...]。

你能帮我吗？

Answer 1

感谢@bakaDev这是我问题的解决方案：

import re #for natural sorting

filenamelist=[]
txt_path = 'decoded'

_nsre = re.compile('([0-9]+)')
def natural_sort_key(s):
    return [int(text) if text.isdigit() else text.lower()
            for text in re.split(_nsre, s)]   

fnlist = os.listdir(txt_path)

fnlist.sort(key=natural_sort_key)

for filename in fnlist):
  with open(txt_path+"/"+filename) as myfile:
    for line in myfile:
        if "Total Time" in line:

            filenamelist.append(filename)

Python：如何在文件夹中对字母数字文件名进行排序？

1 个答案: