Question

我有两个数组： 1.这里的每个对象都是从数据库中恢复的一行。

    array
      1 => 
        object(stdClass)[41]
          public 'id' => string '1' (length=1)
          public 'class_id' => string '25' (length=2)
          public 'section_id' => string '2' (length=1)
          public 'student_id' => string '1' (length=1)
          public 'date' => string '2011-11-27' (length=10)
          public 'attendance' => string 'present' (length=7)
2 => 
        object(stdClass)[41]
          public 'id' => string '1' (length=1)
          public 'class_id' => string '25' (length=2)
          public 'section_id' => string '2' (length=1)
          public 'student_id' => string '3' (length=1)
          public 'date' => string '2011-11-27' (length=10)
          public 'attendance' => string 'present' (length=7)

2。另一个数组来自我的表单，看起来像这样。

array
  0 => 
    array
      'class_id' => string '25' (length=2)
      'section_id' => string '2' (length=1)
      'student_id' => int 1
      'date' => string '2011-11-27 00:00:00' (length=19)
      'attendance' => string 'present' (length=7)
  1 => 
    array
      'class_id' => string '25' (length=2)
      'section_id' => string '2' (length=1)
      'student_id' => int 2
      'date' => string '2011-11-27 00:00:00' (length=19)
      'attendance' => string 'present' (length=7)

我想做的是：
- 比较这两个并检查关键student_id和日期是否已经在数据库中 - 从表格数据的第二个数组中删除重复数据并插入数据最终结果应该是：

array
  0 => 
    array
      'class_id' => string '25' (length=2)
      'section_id' => string '2' (length=1)
      'student_id' => int 2
      'date' => string '2011-11-27 00:00:00' (length=19)
      'attendance' => string 'present' (length=7)

Answer 1

尝试：

$c = [array_merge][1]($a,$b);

var_dump([array_unique][1]($c));

希望有所帮助

Answer 2

通过将标志SORT REGULAR设置为参数来补充DemoUser的anwer已解决了我的“转换数组到字符串”问题：

$c = array_merge($a,$b);

$d = array_unique($c, SORT_REGULAR);

var_dump($d);

Answer 3

由于您的数组（数据库和表单）都 NOT 完全相同，因此无法调用array_merge或array_unique函数。您将需要迭代数据库行一次，并将返回值存储在单独的基于键值的数组（Map）中。然后遍历表单返回的数组并搜索先前准备好的数组中的键，如果找到则从表单返回的数组中删除该元素。请考虑以下代码段：

// assuming database returned rows are in $rows array
// assuming form returned records are in $forms array

$dbArray = array();
foreach($rows as $r) {
   // need to convert string to int and string to date to match data in both sets
   $dbArray[ array( (int) $r->student_id, strtotime($r->date) ) ] = 1;
}

$diffArray = array();
foreach($forms as $f) {
   $key = array( $f['student_id'], strtotime($f['date']) );
   if (!array_key_exists($key, $dbArray))
      $diffArray[] = $f;
}

// now $diffArray will have the final result you're looking for

如何在php中合并两个没有重复值的数组？

3 个答案: