Question

我试图将两个或多个数组中的一些数字添加到一个数组中。我的问题是，它总是添加另一个索引。

源数组如下所示：

array(
(int) 0 => array(
    'Sale' => array(
        'id' => '1',
        'market_id' => '1',
        'product_ids' => '1,2,3,4,5,6,7,8',
        'date_and_time' => '2014-12-28 00:00:00',
        'money_spent' => '2344',
        'points_given' => '213'
    )
),
(int) 1 => array(
    'Sale' => array(
        'id' => '2',
        'market_id' => '1',
        'product_ids' => '44,3,32,23,12,32',
        'date_and_time' => '2014-12-28 15:25:38',
        'money_spent' => '123',
        'points_given' => '2'
    )
)

）

用于合并数组并从product_ids字段中分解数字的PHP代码

$sales=array();

foreach ($sales_detailed as $sale_detailed): {

$sale_detailed_ids=explode( ',', $sale_detailed['Sale']['product_ids'] );
array_push($sales, $sale_detailed_ids);


} endforeach;

结果是

array(
(int) 0 => array(
    (int) 0 => '1',
    (int) 1 => '2',
    (int) 2 => '3',
    (int) 3 => '4',
    (int) 4 => '5',
    (int) 5 => '6',
    (int) 6 => '7',
    (int) 7 => '8'
),
(int) 1 => array(
    (int) 0 => '44',
    (int) 1 => '3',
    (int) 2 => '32',
    (int) 3 => '23',
    (int) 4 => '12',
    (int) 5 => '32'
)

）

虽然我希望它看起来像这样

array(
(int) 0 => array(
    (int) 0 => '1',
    (int) 1 => '2',
    (int) 2 => '3',
    (int) 3 => '4',
    (int) 4 => '5',
    (int) 5 => '6',
    (int) 6 => '7',
    (int) 7 => '8'
    (int) 8 => '44',
    (int) 9 => '3',
    (int) 10 => '32',
    (int) 11 => '23',
    (int) 12 => '12',
    (int) 13 => '32'
)

）

Answer 1

嗯，从我的观点来看，你只是把它弄错了。使foreach遍历逗号分隔列表并手动添加它而不是推送整个数组。

$sales=array();
foreach ($sales_detailed as $sale_detailed) {
    $sale_detailed_ids = explode( ',', $sale_detailed['Sale']['product_ids'] );
    foreach($sale_detailed_ids as $ids) {
        $sales[] = $ids;
    }
}

http://3v4l.org/hoaVF

Answer 2

您必须将一些自定义代码写入＆＃34;跳过＆＃34;第一级数组，只合并第二级。

function mergeKeepIds($a, $b) {
   $keys = array_unique(array_keys($a) + array_keys($b)); // Grab all the keys.
   $result = [];

   foreach ($keys as $key) {
       $valueA = array_key_exists($key, $a) ? $a[$key] : [];
       $valueB = array_key_exists($key, $b) ? $b[$key] : [];
       $result[$key] = array_merge($valueA, $valueB);
   }

   return $result;
}

如何合并两个数组而不添加另一个索引

2 个答案: