Question

好吧，我一直在网站上工作，但每当我对来自数据库的一些数据使用foreach循环时，我一直都会出现奇怪的显示。我明白了：

2
Posted By: 2
22
Posted By: 2
2H
Posted By: H
HH
Posted By: H
HT
Posted By: T
TT
Posted By: T
TA
Posted By: A
AA
Posted By: A
A

当我使用这个循环时：

    $res = mysql_query("SELECT * FROM `fcat`");
    $resa = mysql_fetch_array($res);
    if(!empty($resa)){
        foreach($resa as $j){
            echo $j['title']."<br />";
            echo "Posted By: ".$j['poster']."<br />";
            echo $j['info'];
        }
    }else{
        echo "Nothing.";
    }

在此数据库中：

id is an int(11)= 2
title is a varchar(65)= Hi
info is a text= Test
creator is a text= Admin

谢谢！

Answer 1

我认为这可能会对您有所帮助：

$res = mysql_query("SELECT * FROM `fcat`");
if(mysql_num_rows($res)>0){
    while($j = mysql_fetch_array($res)){
        echo $j['title']."<br />";
        echo "Posted By: ".$j['poster']."<br />";
        echo $j['info'];
    }
}else{
    echo "Nothing.";
}

Answer 2

mysql_fetch_array返回一个包含数字和关键字的数组

数组mysql_fetch_array（resource $ result [，int $ result_type = MYSQL_BOTH]）

所以，将其改为

mysql_fetch_array($res, MYSQL_ASSOC);

Answer 3

试试这个：

$res = mysql_query("SELECT * FROM `fcat`");
    while($j = mysql_fetch_array($res)){
        echo $j['title']."<br />";
        echo "Posted By: ".$j['poster']."<br />";
        echo $j['info'];
    }

来自Foreach的不寻常输出（）

3 个答案: