我正在编写一种方法,根据CGRect中的触摸位置更改图像和var。我目前正在使用一系列if语句手动反转触摸位置。我不相信这是一种特别有效的方法。
它适用于图像更改,但是对于var更改(我还没有实现),我需要以+1增量从1到100进行缩放。
- (void)touchesMoved:(NSSet *)touches withEvent:(UIEvent *)event {
UITouch *touch = [touches anyObject];
CGPoint point = [touch locationInView: self.view];
if (CGRectContainsPoint(CGRectMake(0, 20, 117, 200), point)) {
if (point.y >= 20 && point.y <= 32) //12
imageA.image = [UIImage imageNamed:@"ChemA-15.png"];
if (point.y >= 33 && point.y <= 45)
imageA.image = [UIImage imageNamed:@"ChemA-14.png"];
if (point.y >= 46 && point.y <= 58)
imageA.image = [UIImage imageNamed:@"ChemA-13.png"];
if (point.y >= 59 && point.y <= 70)
imageA.image = [UIImage imageNamed:@"ChemA-12.png"];
if (point.y >= 71 && point.y <= 82)
imageA.image = [UIImage imageNamed:@"ChemA-11.png"];
if (point.y >= 83 && point.y <= 94)
imageA.image = [UIImage imageNamed:@"ChemA-10.png"];
if (point.y >= 95 && point.y <= 106)
imageA.image = [UIImage imageNamed:@"ChemA-9.png"];
if (point.y >= 107 && point.y <= 118)
imageA.image = [UIImage imageNamed:@"ChemA-8.png"];
if (point.y >= 119 && point.y <= 130)
imageA.image = [UIImage imageNamed:@"ChemA-7.png"];
if (point.y >= 131 && point.y <= 142)
imageA.image = [UIImage imageNamed:@"ChemA-6.png"];
if (point.y >= 143 && point.y <= 154)
imageA.image = [UIImage imageNamed:@"ChemA-5.png"];
if (point.y >= 155 && point.y <= 166)
imageA.image = [UIImage imageNamed:@"ChemA-4.png"];
if (point.y >= 167 && point.y <= 178)
imageA.image = [UIImage imageNamed:@"ChemA-3.png"];
if (point.y >= 179 && point.y <= 190)
imageA.image = [UIImage imageNamed:@"ChemA-2.png"];
if (point.y >= 191 && point.y <= 202)
imageA.image = [UIImage imageNamed:@"ChemA-1.png"];
}
}
有更好的方法吗?感谢您提供的任何帮助。
答案 0 :(得分:3)
您可以计算出您需要的图像:
int image = 15 - (int)((point.y - 20) / 13);
然后从中创建一个字符串并检查边界,如:
if(image >= 1 && image <= 15)
imageA.image = [UIImage imageNamed:
[NSString stringWithFromat: @"ChemA-%d.png", image]];