Question

我如何按时间分组？我尝试了这个，但它给出了错误“无效的列名'时间'。”：

select Count(Page) as VisitingCount, CONVERT(VARCHAR(5), Date, 108) as [Time]
from scr_SecuristLog   
where Date between '2009-05-04 00:00:00' and '2009-05-06 14:58'  
and [user] in (select USERNAME from scr_CustomerAuthorities)  
group by [Time] order by [VisitingCount] asc

Answer 1

尝试

GROUP BY CONVERT(VARCHAR(5),Date, 108)

始终确保按照select子句中没有聚合函数的所有内容进行分组。

Answer 2

[时间]是列别名。尝试

SELECT 
      COUNT(Page) AS VisitingCount
    , CONVERT(VARCHAR(5),Date, 108) AS [Time] 
FROM
    scr_SecuristLog   
WHERE
    Date BETWEEN '2009-05-04 00:00:00' AND '2009-05-06 14:58'  
    AND
    [user] IN (
                SELECT 
                    USERNAME             
                FROM
                    scr_CustomerAuthorities 
                )  
GROUP BY
    CONVERT(VARCHAR(5),Date, 108) 
ORDER BY
    [VisitingCount] ASC

Answer 3

select Count(Page) as VisitingCount,CONVERT(VARCHAR(5),Date, 108) as [Time] from scr_SecuristLog   
where Date between '2009-05-04 00:00:00' and '2009-05-06 14:58'  
and [user] in(select USERNAME             
    from scr_CustomerAuthorities )  
group by CONVERT(VARCHAR(5),Date, 108) order by [VisitingCount] asc

我修改了GROUP BY以包含[Time]的实际表达式，而不是列别名（因为这不能用于GROUP BY，只有ORDER BY }）

Answer 4

看起来Date就是这里的一个列，但它是一个关键字而没有引用。也许这就是问题（尽管没有经过测试）：

select Count(Page) as VisitingCount,CONVERT(VARCHAR(5),[Date], 108) as [Time] from scr_SecuristLog   
where [Date] between '2009-05-04 00:00:00' and '2009-05-06 14:58'  
and [user] in(select USERNAME             
    from scr_CustomerAuthorities )  
group by [Time] order by [VisitingCount] asc

Answer 5

如果您不想重复日期转换（有时计算比简单转换更加强烈），那么您可以使用以下内容：

select * 
from ( select Count(page) .., ... As [Date] from ... where ...) UG
group by UG.[Date]

请注意，有给内部选择提供'UG'名称，并且这种情况最有可能，并且在大多数情况下比在原始分组中重复转换表达式效率低。你的整个表达也可能会改变......但是你知道这是可能的。

如何在SQL中按列分组？

5 个答案: