我在下面添加了代码,抱歉打扰了你这么多代码。参数解析没问题,我用手表检查了一下。我已经放了一些printf
来检查问题可能在哪里,似乎它没有打开文件cat
作为参数接收。它从shell调用为“cat -b file
”
#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
#include <string.h>
#define TRUE 0
#define FALSE 1
void yes(int argc, char *argv[]);
int cat(int argc, char *argv[]);
//#include "cat.h"
//#include "yes.h"
//#include"tee.h"
char buf[50],c[10], *p2,*p, *pch;
int count;
char *matrix[20];
void yes(int argc, char *argv[])
{
int i;
// if (argc >= 2 && *argv[1] == '-')
// {
//printf("ERROR!");
//}
//if (argc == 1)
// {
while (1)
if (puts("y") == EOF)
{
perror("yes");
exit(FALSE);
}
// }
while (1)
for (i = 1; i < argc; i++)
if (fputs(argv[i], stdout) == EOF || putchar(i == argc - 1 ? '\n' : ' ') == EOF)
{
perror("yes");
exit(FALSE);
}
//exit(TRUE);
}
int main(int argc, char *argv[])
{
//p=(char *)malloc(sizeof(char)*50);
do
{
fprintf (stderr, "$ ");
fgets (buf,50,stdin);
p=buf;
fprintf (stderr, "Comanda primita de la tastatura: ");
fputs (buf, stderr);
int i=0,j=0;
//strcpy(p,buf);
strcpy(c,"\0");
while (buf[i] == ' ')
{
i++;
p++;
}
if (buf[i] == '#')
fprintf (stderr, "Nici o comanda, ci e un comentariu!\n");
else
{
j=0;
while (buf[i] != ' ' && buf[i] != '\n')
{
i++;
j++;
}
strncpy (c,p,j);
fprintf (stderr, "%s\n",c);
if (strcmp (c,"yes") == 0)
{
p2 = p+j+1;
pch = strtok (p2," ");
count = 0;
while (pch != NULL)
{
//printf ("%s\n",pch);
matrix[count] = strdup(pch);
pch = strtok (NULL, " ");
count++;
}
yes(count, matrix);
fprintf (stderr, "Aici se va executa comanda yes\n");
}
else if (strcmp (c,"cat") == 0)
{
p2 = p+j+1;
pch = strtok (p2," ");
count = 0;
while (pch != NULL)
{
//printf ("%s\n",pch);
matrix[count] = strdup(pch);
pch = strtok (NULL, " ");
count++;
}
cat(count,matrix);
fprintf (stderr, "Aici se va executa comanda cat \n");
}
else if (strcmp (c,"tee") == 0)
{
//tee();
fprintf(stderr, "Aici se va executa comanda tee\n");
}
fprintf (stderr, "Aici se va executa comanda basename\n");
strcpy(buf,"\0");
}
}
while (strcmp(c, "exit") != 0);
fprintf (stderr, "Terminat corect!\n");
return 0;
}
int cat(int argc, char *argv[])
{
int c ;
opterr = 0 ;
optind = 0 ;
char number = 0;
char squeeze = 0;
char marker = 0;
fprintf(stderr,"SALUT< SUNT IN FUNCTIZE>\n");
while ((c = getopt (argc, argv, "bnsE")) != -1)
switch (c)
{
case 'b' :
number = 1;
break;
case 'n' :
number = 2;
break;
case 'm' :
marker = 1;
break;
case 's' :
squeeze = 1;
break;
case 'E' :
marker = 1;
break;
}
if (optind + 1 != argc)
{
fprintf (stderr, "\tWrong arguments!\n") ;
return -1 ;
}
FILE * fd = fopen (argv[optind], "r");
printf("am deschis fisierul %s ",argv[optind]);
if (fd == NULL)
{
printf("FISIER NULL asdasdasdasdasd");
return 1;
}
char line[1025];
int line_count = 1;
while (!feof(fd))
{
fgets(line, 1025, fd);
printf("sunt in while :> %s",line);
int len = strlen(line);
if (line[len - 1] == '\n')
{
if(len - 2 >= 0)
{
if(line[len - 2] == '\r')
{
line[len - 2] = '\0';
len -= 2;
}
else
{
line[len - 1] = '\0';
len -= 1;
}
}
else
{
line[len - 1] = '\0';
len -= 1;
}
}
if (squeeze == 1 && len == 0)
continue;
if (number == 1)
{
fprintf (stdout, "%4d ", line_count);
line_count++;
}
else if (number == 2)
{
if (len > 0)
{
fprintf (stdout, "%4d ", line_count);
line_count++;
}
else
fprintf (stdout, " ");
}
fprintf(stdout, "%s", line);
if (marker == 1)
fprintf(stdout, "$");
fprintf(stdout, "\n");
}
fclose (fd);
return 0 ;
}
答案 0 :(得分:3)
问题在于,当您使用fgets
时,它会在字符串中包含换行符。因此,当您传递文件名时,它会附加一个\n
字符,该字符在输入命令时输入。因此传递的文件名不正确。可以在这些线上(仅指针)获取新线路:
char *filename = strtok(argv[optind], "\n");
if( filename == NULL)
{
/*What the .... */
Handle error!
}
FILE * fd = fopen (filename, "r");
printf("am deschis fisierul %s ",argv[optind]);
if (fd == NULL)
{
printf("FISIER NULL asdasdasdasdasd");
return 1;
}
希望这有帮助!
PS:调试过程
fopen
失败时,会设置errno
。要使用strerror(errno);
或perror
获取确切错误。因此,在perror("fopen");
中添加if(fd == NULL)
会显示fopen : No such file or directory
。接下来打印文件名为fprintf(stderr, "\n |%s|\n", argv[optind]);
,显示带换行符的文件名,即
|hello.txt
|
...然后看到fgets
。啊!来自那里的新行