Question

可能重复：
Create a function that opens a file and creates a dictionary

我们有一个主要功能用于：

编写以下两个函数：

init_dictionary(file_string, sunspot_dict)
此函数将要打开的文件的名称和空字典作为参数。它没有返回值，但确实用字符串填充字典。关键应该是年份;数据应该是当年几个月的太阳黑子数据列表。

主要功能是：

def main():
sunspot_dict = {}
file_str = raw_input("Open what data file: ")
keep_going = True
while keep_going:
    try:
        init_dictionary(file_str, sunspot_dict)
    except IOError:
        print "Data file error, try again"
        file_str = raw_input("Open what data file: ")    
        continue
    print "Jan, 1900-1905:", avg_sunspot(sunspot_dict, (1900,1905),(1,1))
    print "Jan-June, 2000-2011:", avg_sunspot(sunspot_dict, (2000,2011), (1,6))
    print "All years, Jan:", avg_sunspot(sunspot_dict, month_tuple=(1,1))
    print "All months, 1900-1905:", avg_sunspot(sunspot_dict, year_tuple=(1900,1905))
    try:
        print "Bad Year Key example:", avg_sunspot(sunspot_dict, (100,1000), (1,1))
    except KeyError:
        print "Bad Key raised"
    try:
        print "Bad Month Index example:", avg_sunspot(sunspot_dict, (2000,2011), (1,100))
    except IndexError:
        print "Bad Range raised"
    keep_going = False
print "Main function finished normally."

我不知道从哪里开始！请帮忙！

给出的文件是x轴上的月份和1749 - 2011年的数字填充数字

Answer 1

在Python中阅读有关IO的更多信息....

您需要打开文件，提取其内容，然后填充您的字典......

查看Input-Output in Python

提示是看这个例子，他们试图从文件中创建一个字典.... reading file to dictionary

从文件制作字典

1 个答案: