C#XmlNode具有祖先类型

时间:2011-11-10 08:17:54

标签: c# xmldocument xmlnode ancestor

我有一个XmlDocument,格式如下。如果我执行以下搜索

XmlNode title = xmlDoc.SelectNodes("//Book/Title[contains(., \"Title3\")]");

我将找回一个标题的XmlNode。我怎么知道这本书是否属于出版物?我并不总是假设title.ParentNode.ParentNode.ParentNode存在。应该有一种直观的方式说:

if(title.hasAncestor("Publication") != null)
{
    // do whatever
}

非常感谢任何帮助

<Publications>
    <Novel>
        <Book>
            <Title>Title1</Title>
            <Author>Author1</Author>
            <Year>2000</Year>
        </Book>
        <Book>
            <Title>Title2</Title>
            <Author>Author2</Author>
            <Year>2000</Year>
        </Book>
    </Novel>
    <History>
        <Book>
            <Title>Title3</Title>
            <Author>Author3</Author>
            <Year>2000</Year>
        </Book>
        <Book>
            <Title>Title4</Title>
            <Author>Author4</Author>
            <Year>2000</Year>
        </Book>
    </History>
</Publications>
<StudyGuides>
    <Math>
        <Book>
            <Title>Title5</Title>
            <Author>Author5</Author>
            <Year>2000</Year>
        </Book>
        <Book>
            <Title>Title6</Title>
            <Author>Author6</Author>
            <Year>2000</Year>
        </Book>
    </Math>
    <Science>
        <Book>
            <Title>Title7</Title>
            <Author>Author7</Author>
            <Year>2000</Year>
        </Book>
        <Book>
            <Title>Title8</Title>
            <Author>Author8</Author>
            <Year>2000</Year>
        </Book>
    </Science>
</StudyGuides>

2 个答案:

答案 0 :(得分:0)

您可以使用ancestor轴在XPath中执行此操作:

//Book/Title[contains(., "Title3")][ancestor::Publications]

答案 1 :(得分:0)

/Publications/*/Book/Title[contains(., 'Title3')]