Question

我有一个使用Django-MPTT的模型，它还有一个通过template_name_field使用特定模板的字段。我希望能够使用通用TemplateView，但传入mixin以使用template_name_field。

以下是模型：

from django.db import models
from mptt.models import MPTTModel
from mptt.fields import TreeForeignKey

class CategoryManager(models.Manager):
    def get(self, **kwargs):
        defaults = {}
        defaults.update(kwargs)
        if 'full_slug' in defaults:
            if defaults['full_slug'] and defaults['full_slug'][-1] != "/":
                defaults['full_slug'] += "/"
        return super(CategoryManager, self).get(**defaults)

class Category(MPTTModel):
    title = models.CharField(max_length=255)
    description = models.TextField(blank=True, help_text='A brief description of the category. No HTML allowed.')
    slug = models.SlugField(help_text='Prepopulates from title field.')
    full_slug = models.CharField(max_length=255, blank=True)
    template_name = models.CharField(max_length=70, blank=True, help_text="Example: 'categories/category_parent.html'. If this isn't provided, the system will use 'categories/category_detail.html'.")

    parent = TreeForeignKey('self', null=True, blank=True, related_name='children')

    objects = CategoryManager()

    class Meta:
        verbose_name = 'category'
        verbose_name_plural = 'categories'

    def save(self, *args, **kwargs):
        orig_full_slug = self.full_slug
        if self.parent:
            self.full_slug = "%s%s/" % (self.parent.full_slug, self.slug)
        else:
        self.full_slug = "%s/" % self.slug
        obj = super(Category, self).save(*args, **kwargs)
        if orig_full_slug != self.full_slug:
            for child in self.get_children():
                child.save()
        return obj

    def __unicode__(self):
        return "%s (%s)" % (self.title, self.full_slug)

以下是观点：

from django.core.exceptions import ImproperlyConfigured
from django.core.urlresolvers import reverse
from django.views.generic import TemplateView, DetailView
from django.views.generic.detail import SingleObjectTemplateResponseMixin
from django.utils.translation import ugettext as _
from django.contrib.syndication.views import Feed

from storefront.categories.models import Category

class SimpleCategoryView(TemplateView):

    def get_category(self):
        return Category.objects.get(full_slug=self.kwargs['full_slug'])

    def get_context_data(self, **kwargs):
        context = super(SimpleCategoryView, self).get_context_data(**kwargs)
        context["category"] = self.get_category()
        return context

这是我的网址：

from django.conf.urls.defaults import patterns, include, url
from storefront.categories.models import Category
from storefront.categories.views import CategoryView

urlpatterns = patterns('',
    url(r'^(?P<full_slug>[-\w/]+)', SimpleCategoryView.as_view(template_name='categories/category_detail.html'), name='category_view'),

），

我如何添加mixin以将template_name_field用于我的视图？

Answer 1

您不需要单独的mixin。 TemplateView已经有TemplateResponseMixin，因此您只需覆盖get_template_names子类中的SimpleCategoryView。

class SimpleCategoryView(TemplateView):
    ...
    def get_template_names(self):
        return [self.get_category().template_name]

Answer 2

DetailView应该拥有您需要的一切。您只需要使用DetailView.get_template_names()属性告诉template_name_field哪个字段可以包含模板名称。下面是一个完整的视图定义，它根据url中的slug获取Category。请注意，Category将在模板中以object和category的形式提供。

class SimpleCategoryView(DetailView):
    model = Category
    slug_url_kwarg = 'full_slug'
    slug_field = 'full_slug'
    template_name_field = 'template_name'

如何在Django TemplateView中传入mixin for template_name_field？

2 个答案: