如何将对象传递给TemplateView?

时间:2017-02-09 06:02:52

标签: django django-templates

我只是在学习CBV,并且很难将对象传递给TemplateView。这非常令人沮丧,因为我知道这应该是非常基本的。

这是我的views.py:

from __future__ import absolute_import
from django.views import generic
from company_account.models import CompanyProfile

class CompanyProfileView(generic.TemplateView):
    template_name = 'accounts/company.html'

    def get_context_data(self, **kwargs):
        context = super(CompanyProfileView, self).get_context_data(**kwargs)
        return CompanyProfile.objects.all()

这是我的Models.py:

from __future__ import unicode_literals

from django.db import models
from django.contrib.auth.models import User
from django.core.urlresolvers import reverse

class CompanyProfile(models.Model):
    company_name = models.CharField(max_length=255)

    def __str__(self):
        return self.company_name

这是urls.py

urlpatterns = [
    url(r'^accounts/companyprofile/$', CompanyProfileView.as_view()),
]

最后,这是模板:

{% extends '_layouts/base.html' %}

{% block title %}Company Profile{% endblock %}

{% block headline %}<h1>Company Profile</h1>{% endblock %}

{% block content %}{{ CompanyProfile.company_name }}{% endblock %}

我错过了什么?提前感谢您的帮助。

1 个答案:

答案 0 :(得分:2)

模板无法读取模型CompanyProfile。在获得任何属性之前,必须先创建模型的实例。

假设您有CompanyProfile的几个实例:

CompanyProfile.objects.get(pk = 1) - &gt;这有一个company_name =&#34;阿迪达斯&#34; CompanyProfile.objects.get(pk = 2) - &gt;这有一个company_name =&#34; Nike&#34;

假设你要展示耐克和阿迪达斯。

然后,您可以这样做:

class CompanyProfile(models.Model):
   company_name = models.CharField(max_length=25)

class CompanyProfileView(views.TemplateView):
   template_name = 'my_template.html'

   def get_context_data(self, **kwargs):
       context = super(CompanyProfileView, self).get_context_data(**kwargs)
       # here's the difference:
       context['company_profiles'] = CompanyProfile.objects.all()
       return context

然后,渲染你的模板:

{% for company in company_profiles %}
    {{ company.company_name }}
{% endfor %}

我希望有所帮助!