Question

我有

int chop (char* input, unsigned int length)
{
 for (int chopper = 0; chopper < = length; chopper++)
 {
   //how to pass 1byte this input to another function
   //Will this for loop help?
 }
}

如何从此输入中提取一个字节以供进一步处理？谢谢

Answer 1

int chop (char* input, unsigned int length)
{
 for (int chopper = 0; chopper < = length; chopper++)
 {
   doSomething(input[chopper]);
 }
}

Answer 2

有什么问题

 for (int chopper = 0; chopper < length; chopper++)
 {
   //how to pass 1byte this input to another function
   //Will this for loop help?
   unsigned char byte = input[chopper];
   /// do whatever with the byte, and then move on to the next one
 }

注意，chopper < = length可能不对，您很可能需要chopper < length。

Answer 3

您可以将指针视为只读数组，因此您可以像这样引用输入的单个字符：

input[chopper]

您还应该将循环的结束条件更改为

chopper < length

否则你的循环的最后一次迭代将引用超出输入大小的内存位置（从0开始）。

提取字节C ++

3 个答案: