Question

我正在我的网站上运行订阅。我有1,3,6和12个月的订阅，我希望用户能够随时更改订阅。但是，我需要计算用户在短期内报名时需要支付的金额，而不是相对便宜，较长的金额。

我创建了这个函数optimized_subscription_total($active_sub_time,$arr_sub_values)，以便它准确地返回这笔钱。

<?php 


function optimized_subscription_total($active_sub_time,$arr_sub_values)
{

    // This function takes a row from the DB where prices for each period of time usage is listed. there are prices for 1 month, 3 months,6 and 12 months.

    // when the user has subscribed for 12 months, and the user asks for a refund, after they used 9 months and 6 days for example, the system treats the refund as if they subscribed for (in months) COST_6 + COST_3 + (COST_1/30)*6 
    // the result of the function is then subtracted from the amount they actually paid and is considered the refund.

    // $arr_sub_values is the associative row from the DB, containing the prices
    // $active_sub_time is measured in months and is a double

$result=0;


while(($active_sub_time-12)>=0)
{
    $active_sub_time-=12;
    $result+=($arr_subscription_values['COST_12']);
}

while(($active_sub_time-6)>=0)
{
    $active_sub_time-=6;
    $result+=($arr_subscription_values['COST_6']);
}
while(($active_sub_time-3)>=0)
{
    $active_sub_time-=3;
    $result+=($arr_subscription_values['COST_3']);
}

while(($active_sub_time-1)>=0)
{
    $active_sub_time-=1;
    $result+=($arr_subscription_values['COST_1']);
}

if($active_sub_time>0)
    $result+=($active_sub_time)*($arr_subscription_values['COST_1']);

return $result;

}



$datetime1 = date_create('2009-12-11');
$datetime2 = date_create('2010-11-09');
$interval = date_diff($datetime1, $datetime2);
$num_of_months = ($interval->format('%y'))*12+($interval->format('%m'))+($interval->format('%a'))/30;
echo "<br />";

$v = array('COST_1'=>'3.99','COST_3'=>'9.99','COST_6'=>'15.99','COST_12'=>'25.99');
echo "OPT value for $num_of_months months=" . optimized_subscription_total($num_of_months, $v);


?>

奇怪的是，在刷新此代码后，我只会在7到10次后出现错误。所以我得到了：

OPT value for 10 months=M.97

因此在这里。我想我需要一个浮点数，不是吗？

我期待功能的结果应该是“10个月的OPT值= 29.97”，因为它应该花费COST_6 + COST_3 + COST_1 ......但是我得到了奇怪的M.97，有时像POKHHHG这样的东西0.97

Answer 1

我会将逻辑更改为以下内容并查看是否仍然生成错误。我认为这是一个更清晰，更容易调试。虽然只是用不同的方式解释，但它与你的相同。

while($active_sub_time>=12)
{
    $active_sub_time-=12;
    $result+=($arr_subscription_values['COST_12']);
}

while($active_sub_time>=6)
{
    $active_sub_time-=6;
    $result+=($arr_subscription_values['COST_6']);
}
while($active_sub_time>=3)
{
    $active_sub_time-=3;
    $result+=($arr_subscription_values['COST_3']);
}

while($active_sub_time>=1)
{
    $active_sub_time-=1;
    $result+=($arr_subscription_values['COST_1']);
}

我还要做的是在函数顶部添加debug cod。

echo "<br>$active_sub_time" // debug code include at the top

如果有任何垃圾被发送到函数本身，这将给你一个想法。

如果上述方法无法解决问题，我还会在所有块中添加此测试功能。

if (!is_numeric($result))
{
    echo"<br> Bug occurred";break; // print other values if necessary
}

计算错误，请帮我找一下？

1 个答案: