Objective-C提取rangeOfString返回的范围的索引：

Question

如何从

中提取NSUInteger index

NSRange range = [string rangeOfString: substring]

所以我可以在[array objectAtIndex:index]？

中写下这个索引

Answer 1

NSRange range = [string rangeOfString:substring];
NSUInteger index = range.location;
//...

Answer 2

// make sure that the substring was actually found:
NSRange result = [string rangeOfString:substring];

if (result.location != NSNotFound)
{
    // make sure that the index exists in the array
    if (result.location < [array count])
    {
        id someObj = [array objectAtIndex:result.location];
        // do something cool with someObj here
    }
}