Question

您好我有一个这样的字符串：

Results for: 123D12 
2010

2009

2008

2007

2006

YEAR: 2006 WEEK: 2 PRODIDNUM: 37911
 ACCESSKEY: FA3540B52F

2005

2004

YEAR: 2004 WEEK: 22 PRODIDNUM: 46178
 ACCESSKEY: 58B2509373

我想发现ACCESSKEY帮助我获得十六进制（在这种情况下是FA3540B52F和58B2509373）。

问题是，当我使用rangeOfString获取accesskey时，它只会停止到第一个！这是我的代码：

if ([strippedString rangeOfString:@"ACCESSKEY"].location != NSNotFound ) {
    NSUInteger int1=[strippedString rangeOfString:@"ACCESSKEY"].location;

    NSString *finssid = [strippedString substringWithRange:NSMakeRange(int1+11,10)];
    NSLog(@"Output = Found it %d \n",int1);

    NSLog(@"Output =%@ \n \n",finssid);    
}

我在这里做错了什么？

Answer 1

试试这个：

NSRange searchRange = NSMakeRange(0, [strippedString length]);
BOOL keepGoing = YES;

// Find all ssid
while (keepGoing) {
    NSRange accessWord = [strippedString rangeOfString:@"ACCESSKEY" options:NSCaseInsensitiveSearch range:searchRange];
    if (accessWord.location != NSNotFound) {
        // since we have found the access key, we can assume somethings
        // ACCESSKEY: FA3540B52F
        int pos = accessWord.location + 11;
        NSString *ssid = [strippedString substringWithRange:NSMakeRange(pos, pos + 10)];

        NSLog(@"SSID: %@", ssid);

        // reset our search up a little for our next loop around
        searchRange = NSMakeRange(pos, [strippedString length] - pos);
    } else {
        keepGoing = NO;
    }
}

`

Answer 2

使用rangeOfString:options:range:代替rangeOfString:。保存您找到匹配的索引，然后在索引之后使用range:参数start。通过这种方式，您可以循环播放并且之前的匹配超出了您正在查看的范围。

iPhone rangeOfString

2 个答案: