将 多行 从另一个表中更新为一个表,基于每个表中的一个相等(user_id)。
这两个表都有一个user_id
列。当t2
列相等时,需要将t1
中的数据插入user_id
。
提前感谢您提供的任何帮助。
答案 0 :(得分:50)
update
table1 t1
set
(
t1.column1,
t1.column2
) = (
select
t2.column1,
t2.column2
from
table2 t2
where
t2.column1 = t1.column1
)
where exists (
select
null
from
table2 t2
where
t2.column1 = t1.column1
);
或者这个(如果t2.column1< => t1.column1是多对一的,其中任何一个都很好):
update
table1 t1
set
(
t1.column1,
t1.column2
) = (
select
t2.column1,
t2.column2
from
table2 t2
where
t2.column1 = t1.column1
and
rownum = 1
)
where exists (
select
null
from
table2 t2
where
t2.column1 = t1.column1
);
答案 1 :(得分:25)
如果要使用t2中的数据更新t1中的匹配行,则:
update t1
set (c1, c2, c3) =
(select c1, c2, c3 from t2
where t2.user_id = t1.user_id)
where exists
(select * from t2
where t2.user_id = t1.user_id)
“where exists”部分用于防止在不存在匹配的情况下将t1列更新为null。
答案 2 :(得分:14)
merge into t2 t2
using (select * from t1) t1
on (t2.user_id = t1.user_id)
when matched then update
set
t2.c1 = t1.c1
, t2.c2 = t1.c2
答案 3 :(得分:5)
如果记录已存在于t1(user_id匹配)中,则不是插入,除非您乐意创建重复的user_id。
您可能想要更新吗?
UPDATE t1
SET <t1.col_list> = (SELECT <t2.col_list>
FROM t2
WHERE t2.user_id = t1.user_id)
WHERE EXISTS
(SELECT 1
FROM t2
WHERE t1.user_id = t2.user_id);
希望它有所帮助...
答案 4 :(得分:2)
你总是可以使用并省略“当不匹配的部分”
merge into table1 FromTable
using table2 ToTable
on ( FromTable.field1 = ToTable.field1
and FromTable.field2 =ToTable.field2)
when Matched then
update set
ToTable.fieldr = FromTable.fieldx,
ToTable.fields = FromTable.fieldy,
ToTable.fieldt = FromTable.fieldz)
when not matched then
insert (ToTable.field1,
ToTable.field2,
ToTable.fieldr,
ToTable.fields,
ToTable.fieldt)
values (FromTable.field1,
FromTable.field2,
FromTable.fieldx,
FromTable.fieldy,
FromTable.fieldz);