根据另一个表数据更新一个表中的数据

Question

我有如下表A和表B.两者都有帐号和ID。 我想从表A中找出表B中帐号的ID，并用表A中的ID值更新表B.我想让表A看起来像表B.如何实现这个目标？

我试过

select distinct  A.ID,A.ACCTNO,B.ACCTNO from  TableA as A
inner join TableB as B on A.ACCTNO = B.ACCTNO

我的输出应该是：

Answer 1

将JOIN与update一起使用。

<强>查询

update t1
set t1.ID = t2.ID
from TableB t1
join TableA t2
on t1.ACCTNO = t2.ACCTNO;

<强>更新

用于填充空行。

<强>查询

;with cte as(
    select rn = row_number() over(
        partition by acctno
        order by acctno
    ), *
    from TableB 
),
cte2 as(
    select rn = row_number() over(
        order by acctno
    ), *
    from TableA
    where not exists(
        select 1 from TableB
        where TableA.acctno = TableB.acctno
    )
)
update t1
set t1.Id = t2.Id,
t1.Acctno = t2.Acctno
from cte t1
join cte2 t2
on t1.rn = t2.rn
where t1.Id is null;

Answer 2

基于加入更新...您还可以在ACCTNO中忽略null 以获得更好的效果......

update B
set B.ID=A.ID
from TableB as B
join TableA as A
on  A.ACCTNO = B.ACCTNO
where B.ACCTNO is not null;

Answer 3

使用此查询： -

update t2
set t2.id=t1.id
from tableB t2
inner join tableA t1
on t2.acctno=t1.acctno

Answer 4

您需要将此查询运行到所需的输出

update b set b.ID = a.ID 
from TableB as b 
left join TableA as a ON a.ACCTNO = b.ACCTNO 
where b.ACCTNO IS NOT null;

和

WITH CTE
     AS (SELECT T1.ID AS TABLEA_ID,
                T1.ACCTNO  AS TABLEA_ACCID,
                T2.ID AS TABLEB_ID,
                T2.ACCTNO   AS TANLEB_ACCID
         FROM   TableA T1
                INNER JOIN TableB T2
                  ON T1.ACCTNO= T2.ACCTNO)
UPDATE CTE
SET    TABLEA_ID= TABLEB_ID

Answer 5

带有CTE

{{1}}

希望它的工作!!

快乐编码!!

Answer 6

以下SQL将使用表A中ID与acctno匹配的ID填充表B.

UPDATE table_b
SET ID=table_a.id
FROM table_b
INNER JOIN table_a on table_b.acctno=table_a.acctno