Question

我遇到这种情况，我希望从3个不同的数据库中获取数据，例如events，content和media，如下所示：

events

-------------------------
| e_id  | e_title       |
-------------------------
| 1 | event 1   |
| 2 | event 2   |
| 3 | event 3   |
-------------------------

content

-------------------------
| c_id  | c_title       |
-------------------------
| 1 | first event   |
| 2 | second event  |
| 3 | third event   |
-------------------------

media

-------------------------
| m_id  | m_title       |
-------------------------
| 1 | picture 1 |
| 1 | picture 2 |
| 1 | picture 3 |
-------------------------

现在我想通过三个图片从事件1获取信息，所以我有以下查询


$result = mysql_query("
SELECT  events.e_id, events.e_title, content.c_id, content.c_title, media.m_id, media.m_content
FROM events 
INNER JOIN content 
ON events.e_id = content.c_id
INNER JOIN media 
ON events.e_id = media.m_id
WHERE events.e_id = '1'");



Now the point is, when i use 

$show = mysql_fetch_assoc($result); 
echo($show['e_title']." - ".$show['m_title'])

I only get picture 1

when i use 

while($show = mysql_fetch_assoc($result)){ 
echo($show['e_title']." - ".$show['m_title']);}

i get three times event 1

How can i combine this that my output will be something like:

event 1
 * picture 1
 * picture 2
 * picture 3


?

EDIT:

The solution below works fine, but now i have the following that doesn't work

while($show = mysql_fetch_assoc($result)){
    if($show['e_title'] !== $last_title){
        echo("<h3>".$show['e_title']."</h3>\n<ul>\n");
    }
    echo("\t<li>".$show['m_title']."</li>\n");
    if($show['e_title'] !== $last_title){
        echo("\t</ul>\n");
    }
    $last_title = $show['e_title'];
}


How can i achieve that my output will be like:

Event 1
 * picture 1
 * picture 2
 * picture 3

More info about event 1 (not shown in example)

Answer 1

在每次循环迭代中，将最近使用过的e_title存储在$last_title中，并且只有在更改后才会将其回显（$show['e_title'] !== $last_title）：

$last_title = "";
while($show = mysql_fetch_assoc($result)){ 

  // Display the title if it has changed
  if ($show['e_title'] !== $last_title) {
    echo $show['e_title'] . "\n";
  }
  echo "- " . $show['m_title'] . "\n";

  // Store the title to check in the next loop iteration
  $last_title = $show['e_title'];
}

更新如果我了解您要对此进行的操作，则需要测试是否有<ul>打开，如果您这样做，请在开始新{之前关闭它{1}}而不是在循环结束时关闭它。

<h3>

连接表中的多个值

1 个答案: