Question

我正在尝试根据多个表格的动态计算生成一个显示未结余额的报表。目前，此报告是使用运行查询的服务器端语言生成的，循环查询，并针对结果运行另一个查询。我的目标是在MSSQL中执行所有计算。

以下是包含一些示例数据的表/列：

TEST_ORDER表

orderid    customerid   serviceamount
1001       2001                 75.00
1002       2002                 85.00
1003       2001                 25.00
1004       2003                 10.00

TEST_CUSTOMER表

customerid    customername
2001          'Initech'
2002          'Dunder Mifflin'
2003          'Paper Street Soap Co'

TEST_ORDERITEM表

orderitemid    orderid    itemamount
5001           1001            50.00
5002           1001           150.00
5003           1002            15.00
5004           1004           200.00
5005           1004           200.00

TEST_TRANSACTION表

transactionid    orderid    amount
9001             1001        75.00
9002             1002        25.00
9003             1002        50.00
9004             1003        55.00
9005             1001        50.00
9006             1001       150.00

我正在寻找的结果是：

orderid  customername           totalorder   totalpaid     balance
1001     'Initech'                  275.00      275.00        0.00
1002     'Dunder Mifflin'           100.00       75.00      -25.00
1003     'Initech'                   25.00       55.00       30.00
1004     'Paper Street Soap Co'     410.00        0.00     -410.00

以下是我提出的查询：

SELECT 
    o.orderid, c.customername, o.serviceamount,
    (o.serviceamount + SUM( i.itemamount )) AS totalorder,
    SUM( t.amount ) AS totalPaid,
    ( SUM( t.amount ) - (o.serviceamount + SUM( i.itemamount )) ) AS balance

FROM 
    test_order o
    INNER JOIN test_customer c ON o.customerID = c.customerID
    LEFT OUTER JOIN test_transaction t ON o.orderID = t.orderID
    LEFT OUTER JOIN test_orderitem i ON o.orderID = i.orderID

WHERE 
    1=1

GROUP BY 
     o.orderid, c.customername, o.serviceamount,
     o.serviceamount

以下是结果：

orderid  customername           totalorder   totalpaid     balance
1001     'Initech'                  675.00      550.00     -125.00
1002     'Dunder Mifflin'           115.00       75.00      -40.00
1003     'Initech'                    null       55.00        null
1004     'Paper Street Soap Co'     410.00        null        null

我遇到的问题是： 1. test_orderitem中的记录是重复的，例如对于订单1002，服务金额为85美元，只有一个订单项目为15美元，但是，总订单金额为115美元。我认为这个问题与JOIN迭代两次有关。 2.当没有返回记录时出现'null'（显而易见的原因）。我还没有开始研究这个问题，因为我一直在使用MySQL进行测试，我想在将其重新引入MSSQL之前弄清楚JOIN问题。

感谢您提供任何帮助......

Answer 1

对于MS-SQL：在这里，只需用最终查询替换最终查询中的表名。

DECLARE @Test_Order TABLE (orderid int, customerid int, serviceamount money)
INSERT INTO @Test_Order(orderid,customerid,serviceamount)
SELECT 1001,2001,75.00 UNION ALL
SELECT 1002,2002,85.00 UNION ALL
SELECT 1003,2001,25.00 UNION ALL
SELECT 1004,2003,10.00

DECLARE @Test_Customer TABLE (customerid int, customername varchar(100))
INSERT INTO @Test_Customer(customerid,customername)
SELECT 2001,'Initech' UNION ALL
SELECT 2002,'Dunder Mifflin' UNION ALL
SELECT 2003,'Paper Street Soap Co'

DECLARE @Test_OrderItem TABLE (orderitemid int, orderid int, itemamount money)
INSERT INTO @Test_OrderItem (orderitemid, orderid, itemamount)
SELECT 5001,1001,50.00 UNION ALL
SELECT 5002,1001,150.00 UNION ALL
SELECT 5003,1002,15.00 UNION ALL
SELECT 5004,1004,200.00 UNION ALL
SELECT 5005,1004,200.00

DECLARE @Test_Transaction TABLE (transactionid int, orderid int, amount money)
INSERT INTO @Test_Transaction (transactionid, orderid, amount)
SELECT 9001,1001,75.00 UNION ALL
SELECT 9002,1002,25.00 UNION ALL
SELECT 9003,1002,50.00 UNION ALL
SELECT 9004,1003,55.00 UNION ALL
SELECT 9005,1001,50.00 UNION ALL
SELECT 9006,1001,150.00


SELECT O.orderid, 
       C.customername, 
       SUM(ISNULL(O.serviceamount,0)+ISNULL(I.itemamount,0)) AS totalorder, 
       SUM(ISNULL(T.amount,0)) AS totalpaid,
       (SUM(ISNULL(T.amount,0))) - (SUM(ISNULL(O.serviceamount,0)+ISNULL(I.itemamount,0))) as balance
FROM @Test_Customer C
JOIN @Test_Order O
   ON C.customerid=O.customerid
LEFT JOIN (SELECT orderid, SUM(itemamount) AS itemamount FROM @Test_OrderItem GROUP BY orderid) I
   ON O.orderid=I.orderid
LEFT JOIN (SELECT orderid, SUM(amount) AS amount FROM @Test_Transaction GROUP BY orderid) T
   ON O.orderid=T.orderid
GROUP BY O.orderid, C.customername
ORDER BY O.orderid, C.customername

Answer 2

http://sqlfiddle.com/#!9/ae0be/1

SELECT 
  o.orderid,
  c.customername,
  (coalesce(o.serviceamount,0)+coalesce(i.itemsum,0)) totalorder,
  t.t_sum totalpaid,
  (coalesce(t.t_sum,0)-coalesce(o.serviceamount,0)-coalesce(i.itemsum,0)) balance
FROM TEST_ORDER o
LEFT JOIN (
  SELECT orderid, SUM(itemamount) itemsum
  FROM TEST_ORDERITEM
  GROUP BY orderid
) i
ON o.orderid = i.orderid
LEFT JOIN (
  SELECT orderid, SUM(amount) t_sum
  FROM TEST_TRANSACTION
  GROUP BY orderid
) t
ON o.orderid = t.orderid
LEFT JOIN TEST_CUSTOMER c
ON o.customerid = c.customerid
ORDER BY o.orderid

Answer 3

尝试一下：

SELECT
    summary.orderid,
    summary.customername,
    summary.totalorder,
    summary.totalpaid,
    summary.totalorder - summary.totalpaid AS balance
FROM
    (SELECT
        o.orderid,
        c.customername,
        (SELECT SUM(oi.itemamount) FROM test_orderitem oi WHERE oi.orderid = o.orderid) AS totalorder,
        (SELECT IFNULL(SUM(t.amount), 0) FROM test_transaction t WHERE t.orderid = o.orderid) AS totalpaid
    FROM
        test_order o,
        test_customer c
    WHERE
        o.customerid = c.customerid) summary

来自多个JOINed表MSSQL

3 个答案: