我有三个表,Student,StudentClass和Class表。学生表显示学生信息,课程表显示大学中正在进行的课程,学生课程表将学生链接到他们的课堂。问题是,如果我创建一个查询,如果我加入所有三个表,我会在查询中得到重复的行。所以我的问题是,我是否有权利用这三个表创建这样的学生和课堂数据库,或者是否有更有效和更好的方法来实现这一目标。还有其他表,但我希望你只关注这三个表。谢谢
以下是表格:
Student Table:
StudentId(PK) StudentForename StudentSurname Year StudentUsername CourseId(FK)
S1 Mayur Patel 3 u0867587 INFO101
S2 Jim Carlton 3 u1231231 INFO101
S3 Ahmed Seedat 3 u0660663 INFO101
S4 Amar Barot 3 u0954857 INFO101
S5 Richard Davies 3 u0877223 INFO101
StudentClass Table:
ClassId(PK) StudentId(PK)
101 S1
102 S3
103 S1
104 S2
Class Table:
ClassId(PK) Room ClassDay ClassTime ModuleId(FK) CourseId(FK) TeacherId(FK)
101 CW4/10 Thursday 10:00:00 CHI2550 INFO101 T1
102 CW5/01 Wednesday 12:00:00 CHI2565 INFO101 T5
103 CW2/04 Monday 15:00:00 CHT2520 INFO101 T2
104 CW4/10 Thursday 11:00:00 CHI2550 INFO101 T1
下面的查询:(在哪里条款简单查看从表格中输入的文本框中的数据)
SELECT * FROM Module m
INNER JOIN Class cl ON m.ModuleId = cl.ModuleId
JOIN Teacher t ON cl.TeacherId = t.TeacherId
JOIN Session s ON m.ModuleId = s.ModuleId
JOIN Grade_Report gr ON s.SessionId = gr.SessionId
JOIN Student st ON gr.StudentId = st.StudentId
JOIN Course c ON st.CourseId = c.CourseId
WHERE
('".mysql_real_escape_string($sessionid)."' = '' OR gr.SessionId = '".mysql_real_escape_string($sessionid)."')
AND
('".mysql_real_escape_string($moduleid)."' = '' OR s.ModuleId = '".mysql_real_escape_string($moduleid)."')
AND
('".mysql_real_escape_string($courseid)."' = '' OR c.CourseId = '".mysql_real_escape_string($courseid)."')
AND
('".mysql_real_escape_string($classid)."' = '' OR cl.ClassId = '".mysql_real_escape_string($classid)."')
AND
('".mysql_real_escape_string($teacherid)."' = '' OR t.TeacherUsername = '".mysql_real_escape_string($teacherid)."')
AND
('".mysql_real_escape_string($studentid)."' = '' OR st.StudentUsername = '".mysql_real_escape_string($studentid)."')
AND
('".mysql_real_escape_string($year)."' = '' OR st.Year = '".mysql_real_escape_string($year)."')
AND
('".mysql_real_escape_string($grade)."' = '' OR gr.Grade = '".mysql_real_escape_string($grade)."')
答案 0 :(得分:1)
您的架构看起来很好,但您的查询比必要的复杂得多。请尝试以下方法:
select *
from Student s, Class c, StudentClass sc
where s.StudentId = sc.StudentId
and c.ClassId = sc.ClassId
内部联接隐含在此查询中;它应该为您提供与StudentClass
中的行对应的四行。请注意,你会看到Mayur Patel两次:周四在CHI2550一次,周一在CHT2520一次。
如果您想要基于表单字段进行其他过滤,那么这些只是额外的and
子句。
答案 1 :(得分:0)
您的查询将如下所示:
select *
from Student as s
left join
StudentClass as sc
on
s.StudentId = sc.StudentId
right join
Class as c
on
sc.ClassId = c.ClassId