Question

我正在运行一个脚本来从数据库中获取一些帖子。这是脚本：

private function getItems()
    {
        $this->dbConnect($detailsTable);
        mysql_select_db(DB_NAME);
        mysql_query('SET NAMES utf8');
        mysql_query('SET CHARACTER SET utf8');

        $result = mysql_query('SELECT * 
        FROM wp_posts, wp_term_relationships,wp_term_taxonomy 
        WHERE wp_posts.post_status = "publish"  
        AND wp_term_relationships.object_id = id
        AND wp_term_taxonomy.taxonomy= "category"
        AND !(wp_term_taxonomy.term_taxonomy_id = 11)
        AND wp_term_relationships.term_taxonomy_id = wp_term_taxonomy.term_taxonomy_id
        ORDER BY wp_posts.post_date DESC LIMIT 25', LINK);
        mysql_close(LINK);

        $items = '';
        while($row = @mysql_fetch_array($result))
        {
            $title = UTFayar($row['post_title']);
            $content = UTFayar($row['post_content']);

            $items .= '<item id="'.$row["ID"].'">
                <title><![CDATA['.$title.']]></title>
                <description><![CDATA['. $content .']]></description>
                <pubDate>'.date('D, j M Y H:i:s T', strtotime($row['post_date'])).'</pubDate>
                <category>'.$row['post_category'].'</category>
            </item>';
        }
        $items .= '</channel>
                </rss>';

        return $items;
    }

问题是有些帖子属于3类以上。所以我得到了错误的结果，我连续3次以上相同的帖子。我需要这个帖子，即使只有一个类别只能在我的RSS中显示一次。

EIDTED：

这是正确的代码，如果有人需要它：

    private function getItems()
    {
        $this->dbConnect($detailsTable);
        mysql_select_db(DB_NAME);
        mysql_query('SET NAMES utf8');
        mysql_query('SET CHARACTER SET utf8');
        //$result = mysql_query ('SELECT * FROM wp_posts WHERE post_status="publish" and post_category!=17 and post_category!=18 ORDER BY post_date DESC LIMIT 20', LINK);
        $result = mysql_query('SELECT 

ID
, post_title
, post_content
, post_date
, group_concat(DISTINCT post_category ORDER BY post_category DESC SEPARATOR ", " ) as "categories"

FROM wp_posts, wp_term_relationships,wp_term_taxonomy 
        WHERE wp_posts.post_status = "publish"  
        AND wp_term_relationships.object_id = id
        AND wp_term_taxonomy.taxonomy= "category"
        AND !(wp_term_taxonomy.term_taxonomy_id = 11)
        AND wp_term_relationships.term_taxonomy_id = wp_term_taxonomy.term_taxonomy_id
        GROUP BY ID, post_title, post_content, post_date ORDER BY wp_posts.post_date DESC LIMIT 25', LINK);
        mysql_close(LINK);
        $items = '';
        while($row = @mysql_fetch_array($result))
        {
            $title = UTFayar($row['post_title']);
            $content = UTFayar($row['post_content']);



            $items .= '<item id="'.$row["ID"].'">
                <title><![CDATA['.$title.']]></title>
                <description><![CDATA['. $content .']]></description>
                <pubDate>'.date('D, j M Y H:i:s T', strtotime($row['post_date'])).'</pubDate>
                <category>'.$row['categories'].'</category>
            </item>';
        }
        $items .= '</channel>
                </rss>';

        return $items;
    }

Answer 1

问题是你需要以某种方式处理这些类别......将它们卷起来并用逗号显示在列表中可能是处理它的好方法。

mysql有一个很好的函数叫做“GROUP_CONCAT”http://dev.mysql.com/doc/refman/5.0/en/group-by-functions.html#function_group-concat

您的查询将是

    SELECT 

    ID
    , post_title
    , post_content
    , post_date
    , group_concat(DISTINCT post_category ORDER BY post_category DESC SEPARATOR ', ' ) as `categories`

    FROM wp_posts, wp_term_relationships,wp_term_taxonomy 
            WHERE wp_posts.post_status = "publish"  
            AND wp_term_relationships.object_id = id
            AND wp_term_taxonomy.taxonomy= "category"
            AND !(wp_term_taxonomy.term_taxonomy_id = 11)
            AND wp_term_relationships.term_taxonomy_id = wp_term_taxonomy.term_taxonomy_id
GROUP BY    ID
    , post_title
    , post_content
    , post_date             
ORDER BY wp_posts.post_date DESC

php的错误结果

1 个答案: