Question

mysqli_query得到了我的学士学位，if的结果应该是10但是我得到的结果是15.是不是Bachelors没有输出为字符串？怎么做？

<?php $levelofeducation = mysqli_query($con,"SELECT levelofeducation AS value FROM retailmain WHERE id='1'");


    if ($levelofeducation == "Elementary/H School"){echo "0";}
    elseif ($levelofeducation == "JR Coll") {echo "5";}
    elseif ($levelofeducation == "Bachelors"){echo "10";}
    else {echo "15";}
        ?>

Answer 1

看起来你期望从你的mysqli_query调用返回一个字符串，但它实际上返回一个mysqli_result对象（http://php.net/manual/en/mysqli.query.php）。

Answer 2

您不是取结果，只是取道。使用mysqli_fetch_array（）方法

获取结果

   <?php 

 $q = mysqli_query($con,"SELECT levelofeducation AS value FROM retailmain WHERE id='1'");
$levelofeducation=mysqli_fetch_array($q);

if ($levelofeducation == "Elementary/H School"){echo "0";}
elseif ($levelofeducation == "JR Coll") {echo "5";}
elseif ($levelofeducation == "Bachelors"){echo "10";}
else {echo "15";}
    ?>

错误的PHP结果

2 个答案: