我在这里有一个项目，我正在努力解决
我遇到的问题是输出不断出现轻微错误而不是最后两个是E1它是E4而在零中间它应该是11F而不是它像12D这样暗示它主要做正确的事情，但我不明白出了什么问题。这让我疯了。
#include <vector>
#include <fstream>
#include <iostream>
#include <cstdlib>
using namespace std;
//int count = 0;
//GOOD
int hexToInt(vector<char>& c);
vector<char> intToHex(int n);
int hexToInt(char c){
if(c>='A')return c-'A'+10;
else return c-'0';
}
void execute(vector<char>& memory){
// cout << "beb\n";
char A = '0';
char B = '0';
if ((B>'9'&&B<'A')||(B<'0')||(B>'F')) cout << B << endl;
for( size_t i = 0; i<memory.size();i++){
// cout << i << " "<< memory[i] <<endl;
// if(count<100){
// cout << i << " " << memory[i]<<" "<< A << " "<< B <<endl;
// count++;
// cout << A << endl;
// cout << "I: "<< i<< " memory value: "<<memory[i]<<endl;
//}
vector<char> c;
if(memory[i]-'0' == 0){
c.push_back(memory[i+1]);
c.push_back(memory[i+2]);
A = memory[hexToInt(c)];
i+=2;
}
else if(memory[i] -'0' == 1){
c.push_back(memory[i+1]);
c.push_back(memory[i+2]);
memory[hexToInt(c)] = A;
i+=2;
}
else if(memory[i] -'0' == 2){
char temp = A;
A = B;
B = temp;
}
else if(memory[i] -'0' == 3){
int tempy = hexToInt(A)+hexToInt(B);
// if (count<100) cout << tempy<< "aaa"<<endl;
c = intToHex(tempy);
// cout << "LOOK " <<tempy<< temp[0] << " "<<temp[1]<< " "<<A << " "<< B << endl;
//Questionable****
A = c[1];
B = c[0];
}
else if(memory[i] -'0' == 4){
if(A == 'F') A='0';
else A +=1;
}
else if(memory[i] -'0' == 5){
if(A == '0') A='F';
else A -=1;
}
else if(memory[i] -'0' == 6){
if(A=='0'){
c.push_back(memory[i+1]);
c.push_back(memory[i+2]);
if(hexToInt(c)>=240) i+=2;
else i = hexToInt(c)-1;
}
else i+=2;
}
else if(memory[i] -'0' == 7){
c.push_back(memory[i+1]);
c.push_back(memory[i+2]);
if(hexToInt(c)>=240) i+=2;
else i = hexToInt(c)-1;
// i+=2;
}
else /*if(memory[i] -'0' == 8)*/{
if(i!=0) {
for(size_t b = 0; b<memory.size();b++) cout << memory[b];
}
i = memory.size();
// cout <<"yayyyy";
}
if(memory[254]=='E'&& memory[64]=='1'&& memory[65]=='1'&& memory[66]=='F'&&memory[255]=='1')cout <<"fuuuu";
// cout << memory[255]<<endl;
}
cout << endl;
}
int hexToInt(vector<char>& c){
int ret = 0;
int place = 1;
for (int i = c.size()-1; i>=0; i--){
if(c[i]>='A') ret= ret+place*(c[i]-'A'+10);
else ret= ret+place*(c[i]-'0');
place*=16;
}
return ret;
}
//GOOD
vector<char> intToHex(int n){
vector<char> ret;
int place = 16;
while (!(place/16>n)){
int curr = n%place/(place/16);
// if(count<100) cout<<n <<"bbb"<< curr << endl;
if(curr<10) ret.push_back('0'+curr);
else ret.push_back('A'+(curr-10));
n-=curr;
place*=16;
}
while(ret.size()<2) ret.push_back('0');
// if(count<100)cout << ret[0]<<ret[1]<<endl;
int low = 0;
int high = ret.size()-1;
while(low<high){
char temp = ret[low];
ret[low]=ret[high];
ret[high]=temp;
high--;
low++;
}
return ret;
}
int main () {
// int a = 7;
// vector<char> b = intToHex(a);
// for(int i = 0; i<b.size();i++){
// cout << b[i];
// }
// cout <<" " << hexToInt(b) << hexToInt('F')<< " "<< hexToInt('0') << endl;
//GOOD
ifstream ifs("test.txt");
if(!ifs) cout << "wahh\n";
vector<char> memory(256);
while(ifs>>memory[0]){
// cout << "weh\n";
for (size_t i = 1; i<memory.size();i++){
ifs>>memory[i];
cout<<memory[i];
// cout << memory[i];
}
cout<<endl;
// cout << endl;
execute(memory);
}
// vector<int> wtf(256);
// for(int i = 0; i<wtf.size();i++){
// cout << i << " ";
// vector<char> temp = intToHex(i);
// for(int d = 0; d<temp.size(); d++){
// cout <<temp[d];
// }
// cout <<" "<< hexToInt(temp);
// if(i<16) cout<< " "<<hexToInt(intToHex(i)[1]);
// if(i!=hexToInt(intToHex(i)[1])) cout <<" HIOOOOOOOOOOOOOOOOOOOO";
// cout << endl;
//
// }
char c = 'A'+1;
cout << c;
system("PAUSE");
}
答案 0 :(得分：1)
您的操作码INC和DEC错误。如果你看一下ASCII-Table，你会看到'A'不跟随'9'，所以你必须“跳过”这个空白。
执行此操作的最佳方法是将十六进制数字转换为整数，递增/递减整数并将其转换回来。例如，您的DEC操作码可能看起来像这样：
int temp = hexToInt(A);
if(temp == 0)
temp = 0xf;
else
temp -= 1;
vector<char> tempHex = intToHex(temp);
A = tempHex.back();