Question

您的猜测和程序会将结果与列表中的随机词进行比较。如果程序可以找到相同的符号，则会显示，如果不是，您将看到“＃” - 符号。现在，我无法理解为什么“＃”没有表现出色。这是完整的代码。

示例：

apple - 随机词
杏 - 客户的回答

ap #############（15个音节，因为顾客不必知道这个词的长度）

import java.util.Random; import java.util.Scanner;

public class Main {
    private static Scanner scan = new Scanner(System.in);

    public static final int N = 30;

    public static void main(String[] args) {
        String ranWord;
        Random rand = new Random();

        String[] words = new String[N];
        words[0] = "appricot";
        words[1] = "orange";
        words[2] = "cucumber";
        words[3] = "potato";
        words[4] = "tomato";
        words[5] = "cherry";
        words[6] = "banana";
        words[7] = "carrot";
        words[8] = "were";
        words[10] = "very";
        words[11] = "tasty";
        words[12] = "as";
        words[13] = "usual";
        words[14] = "and";
        words[15] = "fresh";
        words[16] = "and";
        words[17] = "tasty";
        words[18] = "passed";
        words[19] = "for";
        words[20] = "cooking";
        words[21] = "a";
        words[22] = "chicken";
        words[23] = "it";
        words[24] = "isn't";
        words[25] = "necessary";
        words[26] = "cook";
        words[27] = "chicken";
        words[28] = "every";
        words[29] = "day";

        System.out.println("Try to guess the word, call Your variant?" + "\n");
        ranWord = words[rand.nextInt(N)];
        System.out.println("Computer guess the word: " + ranWord);

        Computer computer = new Computer(ranWord);

        String customWord = scan.nextLine();
        Customer customer = new Customer(customWord);

        boolean finish = true;
        while (!finish) {
            //customWord = scan.nextLine();
            if (customer.word.equals(computer.ranWord)) {
                System.out.println("Succsesful prompt!");
                finish = true;
            } else {
                checkIsFinish(customWord, ranWord);
                finish = false;
            }
        }
    }

    static void checkIsFinish(String customWord, String ranWord) {
        int minLenghtWord = customWord.length() < ranWord.length() ? customWord.length() : ranWord.length();

        for (int i = 0; i < minLenghtWord; i++) {
            if (customWord.charAt(i) == ranWord.charAt(i)) {
                System.out.print(ranWord.charAt(i));
            } else {
                System.out.print("#");
            }
        }
        for (int i = 0; i < 15 - minLenghtWord; i++) {
            System.out.print("#");
        }
        System.out.println(customWord.length());
     }
    }

Answer 1

这是一个愚蠢的错误。您永远不会输入while因为finish = true一开始。

这样做，

finish = true;
while (finish) {
    //customWord = scan.nextLine();
    if (customer.word.equals(computer.ranWord)) {
        System.out.println("Succsesful prompt!");

    } else {
        checkIsFinish(customWord, ranWord);
    }
    finish = false;

}

或者，

finish = false;
while (!finish) {
    //customWord = scan.nextLine();
    if (customWord.equals(ranWord)) {
        System.out.println("Succsesful prompt!");

    } else {
        checkIsFinish(customWord, ranWord);
    }
    finish = true;

}

无法获得正确的输出

1 个答案: