Question

所有

如果您使用boost池库，您将如何替换以下语句：

MyStruct *someStruct = (MyStruct *) calloc(numOfElements, sizeof(MyStruct));

如果是一个元素，我会这样做：

boost::object_pool<MyStruct> myPool;
MyStruct *someStruct = myPool.malloc();

但由于“numOfElements”是一个变量，我觉得执行malloc（）循环不是一个好主意吗？

Answer 1

我说你需要使用pool_alloc界面：

static pointer allocate(size_type n);
static pointer allocate(size_type n, pointer);
static void deallocate(pointer ptr, size_type n);

来自http://www.boost.org/doc/libs/1_47_0/libs/pool/doc/interfaces.html

的示例

void func()
{
    std::vector<int, boost::pool_allocator<int> > v;
    for (int i = 0; i < 10000; ++i)
        v.push_back(13);
} // Exiting the function does NOT free the system memory allocated by the pool allocator
  // You must call
  //  boost::singleton_pool<boost::pool_allocator_tag, sizeof(int)>::release_memory()
  // in order to force that

提升池替代calloc

1 个答案: