使用Django将html5画布加载到PIL图像中

时间:2011-10-14 23:42:10

标签: javascript python django canvas python-imaging-library

我正在尝试获取html5画布的内容并将其传递给我的django服务器,然后将其用PIL进行操作并保存为PNG。这是我到目前为止所做的:

从HTML表单中,用户单击“更新”按钮,即画布的内容 - 使用canvas.toDataURL() - 被转储到通过POST表单提交的文本框中。最终这将是自动的,但现在不是。

<input type="text" id="canvasData" name="canvasData"/>
<input type='button' value="update" onclick='jscript:updateData();'>
<canvas id="sketch"></canvas>
<script type="text/javascript">
    function jscript:updateData() {
        $('#canvasData')[0].value = $('canvas')[0].toDataURL();
    }
</script>

当发送过来时,canvasData的格式为'data:image / png; base64,iVBORw0KGgoAAAA ... etc ... ='。然后我在django处理它:

from PIL import Image
...
canvasData = request.POST.get('canvasData', '')
im = Image.somehowLoad(canvasData)
...
im.save('canvas.png')

这就是我被困住的地方。我无法弄清楚如何通过PIL将base64编码的数据网址加载到可用的表单中。

谢谢!

编辑:这是底部评论的代码:

>>> d
'data:image/png;base64,iVBORw0K'
>>> d.strip('data:image/png;base64,')
'VBORw0K'

4 个答案:

答案 0 :(得分:18)

import re

datauri = 'data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAAAUAAAAFCAYAAACNbyblAAAAHElEQVQI12P4//8/w38GIAXDIBKE0DHxgljNBAAO9TXL0Y4OHwAAAABJRU5ErkJggg=='

imgstr = re.search(r'base64,(.*)', datauri).group(1)

output = open('output.png', 'wb')

output.write(imgstr.decode('base64'))

output.close()

或者如果您需要将其加载到PIL中:

import cStringIO

tempimg = cStringIO.StringIO(imgstr.decode('base64'))

im = Image.open(tempimg)

答案 1 :(得分:3)

HTML:

<form action="" method="post">
    {% csrf_token %}
    <input type="hidden" name="width" value="">
    <input type="hidden" name="height" value="">
    <input type="hidden" name="image_data" value="">
</form>

使用Javascript:

function submit_pixels(canvas) {
    $('form input[name=image_data]').val(canvas.toDataURL("image/png"));
    $('form input[name=width]').val(canvas.width);
    $('form input[name=height]').val(canvas.height);
    $('form').submit();
}

Django POST请求视图:

# in the module scope
from io import BytesIO
from PIL import Image
import re

# in your view function
image_data = request.POST['image_data']
image_width = int(request.POST['width'])
image_height = int(request.POST['height'])
image_data = re.sub("^data:image/png;base64,", "", image_data)
image_data = base64.b64decode(image_data)
image_data = BytesIO(image_data)
im = Image.open(image_data)
assert (image_width, image_height,) == im.size

在您的设置中增加最大POST大小(例如:~20 MB):

# canvas data urls are large
DATA_UPLOAD_MAX_MEMORY_SIZE = 20_000_000

答案 2 :(得分:0)

在2019年,我使用python3尝试了Acorn答案,我得到了 错误的“ str”对象没有属性“ decode” 所以我做了一些搜索并调整了代码,它在这里起作用了

from binascii import a2b_base64
import re

datauri = 'data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAAAUAAAAFCAYAAACNbyblAAAAHElEQVQI12P4//8/w38GIAXDIBKE0DHxgljNBAAO9TXL0Y4OHwAAAABJRU5ErkJggg=='

imgstr = re.search(r'base64,(.*)', datauri).group(1)

binary_data = a2b_base64(imgstr)

Out = open('image.png', 'wb')
Out.write(binary_data)
Out.close()

答案 3 :(得分:0)

对于Django 3.0和python 3.7 html文件中的代码(在Django中称为模板)

<form method="POST" id="form1">
        {% csrf_token %}
        <canvas id="camera--sensor"></canvas>
        <!-- Camera view -->
        <video id="camera--view" autoplay playsinline></video>
        <!-- Camera output -->
        <img src="//:0" alt="" id="camera--output" onclick="show()"> 
        <!-- Camera trigger -->
        
        <input type="hidden" id="captured_image" name="captured_image">
        <input id="upload_image"  type="submit" onclick="save()" value="Upload the image">
    </form>

在javascript文件中

var canvas;
function save(){
            canvas = document.getElementById('camera--sensor');
            document.getElementById('captured_image').value = canvas.toDataURL('image/png');
          
        }

在Django的views.py文件中

def capture_image(request):
    if request.method=="POST":
        # print("-------",request.POST)
        if request.POST.get('captured_image'):
            captured_image = request.POST.get('captured_image')
            # imgstr = captured_image.decode('base64')
            imgstr = re.search('base64,(.*)', captured_image).group(1)
            imgstr = base64.b64decode(imgstr)
            # print(imgstr)
            tempimg = io.BytesIO(imgstr)

            im = Image.open(tempimg)